Sure, let's break down the solution to the given questions step-by-step.
### 1. Decrypt the Message "RJJY NSAJ SNHJ"
The message "RJJY NSAJ SNHJ" was encrypted using a Caesar cipher with a shift of 5. This means that each letter in the message was shifted 5 places forward in the alphabet to encrypt it. To decrypt it, we need to shift each letter 5 places backward.
Let's first write down the alphabet and shift each letter backwards by 5 places:
- A becomes V
- B becomes W
- C becomes X
- D becomes Y
- E becomes Z
- F becomes A
- G becomes B
- H becomes C
- I becomes D
- J becomes E
- K becomes F
- L becomes G
- M becomes H
- N becomes I
- O becomes J
- P becomes K
- Q becomes L
- R becomes M
- S becomes N
- T becomes O
- U becomes P
- V becomes Q
- W becomes R
- X becomes S
- Y becomes T
- Z becomes U
Let's apply this shift to each letter in "RJJY NSAJ SNHJ":
- R shifts to M
- J shifts to E
- J shifts to E
- Y shifts to T
- (space) stays (space)
- N shifts to I
- S shifts to N
- A shifts to V
- J shifts to E
- (space) stays (space)
- S shifts to N
- N shifts to I
- H shifts to C
- J shifts to E
So, "RJJY NSAJ SNHJ" decrypts to "MEET INVE NICE".
### 2. Compute 18 mod 6
The modulus operation finds the remainder when one number is divided by another. To compute [tex]\(18 \mod 6\)[/tex]:
[tex]\[
18 \div 6 = 3 \quad \text{(remainder 0)}
\][/tex]
Thus,
[tex]\[
18 \mod 6 = 0
\][/tex]
### 3. Compute [tex]\(10 \mod 3\)[/tex]
Similarly, to compute [tex]\(10 \mod 3\)[/tex]:
[tex]\[
10 \div 3 = 3 \quad \text{(remainder 1)}
\][/tex]
Thus,
[tex]\[
10 \mod 3 = 1
\][/tex]
In summary:
1. The decrypted message is "MEET INVE NICE".
2. [tex]\(18 \mod 6 = 0\)[/tex]
3. [tex]\(10 \mod 3 = 1\)[/tex]
