If [tex]$R_1 = 40.0 \Omega$[/tex], [tex]$R_2 = 25.4 \Omega$[/tex], and [tex][tex]$R_3 = 70.8 \Omega$[/tex][/tex], what is the equivalent resistance?

[tex]$R_{\text{eq}} = [?] \Omega$[/tex]



Answer :

To find the equivalent resistance in a series circuit, you simply add up the resistance values of each resistor. This is because in a series circuit, the total resistance is the sum of all the individual resistances.

Given the resistances:
- [tex]\(R_1 = 40.0 \Omega\)[/tex]
- [tex]\(R_2 = 25.4 \Omega\)[/tex]
- [tex]\(R_3 = 70.8 \Omega\)[/tex]

We use the formula for equivalent resistance in a series circuit:

[tex]\[ R_{\text{eq}} = R_1 + R_2 + R_3 \][/tex]

Substituting the given values:

[tex]\[ R_{\text{eq}} = 40.0 \Omega + 25.4 \Omega + 70.8 \Omega \][/tex]

Adding these together:

[tex]\[ R_{\text{eq}} = 136.2 \Omega \][/tex]

Therefore, the equivalent resistance [tex]\( R_{\text{eq}} \)[/tex] is [tex]\( 136.2 \Omega \)[/tex].