Classwork

[tex]\[
\begin{array}{l}
\text{1. } 3(3x + 1) - 10(x + 1) = 0 \\
\text{2. } 5(x + 2) + 3(x - 5) = 19 \\
\text{3. } 4x + 3x - 7 = 5x - (35 - 6x) \\
\text{4. } 4 - 2 - 2(x - 9) - 6(x - 5) = 50 - 6x - 21 \\
\text{5. } 5(x + 3) = 2(3x - 1) + 3(2x + 1)
\end{array}
\][/tex]



Answer :

Let's solve each equation step-by-step:

### 1. [tex]\(3(3x + 1) - 10(x + 1) = 0\)[/tex]

1. Distribute the multiplication:
[tex]\[ 9x + 3 - 10x - 10 = 0 \][/tex]

2. Combine like terms:
[tex]\[ (9x - 10x) + (3 - 10) = 0 \][/tex]
[tex]\[ -x - 7 = 0 \][/tex]

3. Isolate [tex]\(x\)[/tex]:
[tex]\[ -x = 7 \][/tex]
[tex]\[ x = -7 \][/tex]

So, the solution is [tex]\(x = -7\)[/tex].

### 2. [tex]\(5(x + 2) + 3(x - 5) = 19\)[/tex]

1. Distribute the multiplication:
[tex]\[ 5x + 10 + 3x - 15 = 19 \][/tex]

2. Combine like terms:
[tex]\[ (5x + 3x) + (10 - 15) = 19 \][/tex]
[tex]\[ 8x - 5 = 19 \][/tex]

3. Isolate [tex]\(x\)[/tex]:
[tex]\[ 8x = 24 \][/tex]
[tex]\[ x = 3 \][/tex]

So, the solution is [tex]\(x = 3\)[/tex].

### 3. [tex]\(4x + 3x - 7 = 5x - (35 - 6x)\)[/tex]

1. Simplify both sides:
[tex]\[ 7x - 7 = 5x - 35 + 6x \][/tex]

2. Distribute and combine like terms:
[tex]\[ 7x - 7 = 11x - 35 \][/tex]

3. Isolate [tex]\(x\)[/tex]:
[tex]\[ 7x - 11x = -35 + 7 \][/tex]
[tex]\[ -4x = -28 \][/tex]
[tex]\[ x = 7 \][/tex]

So, the solution is [tex]\(x = 7\)[/tex].

### 4. [tex]\(4 - 2 - 2(x - 9) - 6(x - 5) = 50 - 6x - 21\)[/tex]

1. Simplify both sides:
[tex]\[ 2 - 2(x - 9) - 6(x - 5) = 50 - 21 - 6x \][/tex]
[tex]\[ 2 - 2x + 18 - 6x + 30 = 29 - 6x \][/tex]

2. Distribute and combine like terms:
[tex]\[ 50 - 8x = 29 - 6x \][/tex]

3. Isolate [tex]\(x\)[/tex]:
[tex]\[ -8x + 6x = 29 - 50 \][/tex]
[tex]\[ -2x = -21 \][/tex]
[tex]\[ x = \frac{21}{2} \quad \text{or} \quad x = 10.5 \][/tex]

So, the solution is [tex]\(x = \frac{21}{2}\)[/tex] or [tex]\(x = 10.5\)[/tex].

### 5. [tex]\(5(x + 3) = 2(3x - 1) + 3(2x + 1)\)[/tex]

1. Distribute the multiplication:
[tex]\[ 5x + 15 = 6x - 2 + 6x + 3 \][/tex]

2. Combine like terms and simplify:
[tex]\[ 5x + 15 = 12x + 1 \][/tex]

3. Isolate [tex]\(x\)[/tex]:
[tex]\[ 5x - 12x = 1 - 15 \][/tex]
[tex]\[ -7x = -14 \][/tex]
[tex]\[ x = 2 \][/tex]

So, the solution is [tex]\(x = 2\)[/tex].

### Summary
The solutions are:
1. [tex]\(x = -7\)[/tex]
2. [tex]\(x = 3\)[/tex]
3. [tex]\(x = 7\)[/tex]
4. [tex]\(x = \frac{21}{2}\)[/tex]
5. [tex]\(x = 2\)[/tex]