A powered winch is used to pull a sailboat to shore. The winch uses a 900 W motor. If the motor is used for 30 s, how much work does it do?

(Power: [tex]P = \frac{W}{t}[/tex])

A. 0.03 J
B. 30 J
C. 960 J
D. [tex]27,000 \, \text{J}[/tex]



Answer :

To solve this problem, we start with the formula for power, which is given by:

[tex]\[ P = \frac{W}{t} \][/tex]

Where:
- [tex]\( P \)[/tex] is the power,
- [tex]\( W \)[/tex] is the work done,
- [tex]\( t \)[/tex] is the time.

Rearranging the formula to solve for work done, we get:

[tex]\[ W = P \times t \][/tex]

Next, substitute the given values into this equation. We know:
- The power [tex]\( P \)[/tex] is 900 Watts (W),
- The time [tex]\( t \)[/tex] is 30 seconds (s).

So, we plug these values into the formula:

[tex]\[ W = 900 \, \text{W} \times 30 \, \text{s} \][/tex]

Now, calculate the product:

[tex]\[ W = 27000 \, \text{J} \][/tex]

Thus, the work done by the winch is:

[tex]\[ 27000 \, \text{J} \][/tex]

Therefore, the correct answer is:
[tex]\[ 27,000 \, \text{J} \][/tex]