Identifying Slope and [tex]$y$[/tex]-Intercept of a Line

Identify the slope and [tex]$y$[/tex]-intercept of each linear function's equation.

1. slope [tex]$= 1$[/tex]; [tex]$y$[/tex]-intercept at [tex]$-3$[/tex]
2. slope [tex]$= -1$[/tex]; [tex]$y$[/tex]-intercept at [tex]$3$[/tex]
3. slope [tex]$= -3$[/tex]; [tex]$y$[/tex]-intercept at [tex]$1$[/tex]
4. slope [tex]$= 3$[/tex]; [tex]$y$[/tex]-intercept at [tex]$-1$[/tex]



Answer :

Sure, let's identify the slope and [tex]\( y \)[/tex]-intercept for each given linear function's equation.

1. First Linear Function:
- Slope: [tex]\( 1 \)[/tex]
- [tex]\( y \)[/tex]-Intercept: [tex]\( -3 \)[/tex]

So, the equation of the first line in slope-intercept form [tex]\( y = mx + b \)[/tex] is:
[tex]\[ y = 1x - 3 \quad \text{or simply} \quad y = x - 3 \][/tex]

2. Second Linear Function:
- Slope: [tex]\( -1 \)[/tex]
- [tex]\( y \)[/tex]-Intercept: [tex]\( 3 \)[/tex]

The equation of the second line is:
[tex]\[ y = -1x + 3 \quad \text{or} \quad y = -x + 3 \][/tex]

3. Third Linear Function:
- Slope: [tex]\( -3 \)[/tex]
- [tex]\( y \)[/tex]-Intercept: [tex]\( 1 \)[/tex]

The equation of the third line is:
[tex]\[ y = -3x + 1 \][/tex]

4. Fourth Linear Function:
- Slope: [tex]\( 3 \)[/tex]
- [tex]\( y \)[/tex]-Intercept: [tex]\( -1 \)[/tex]

Finally, the equation of the fourth line is:
[tex]\[ y = 3x - 1 \][/tex]

Thus, the slopes and [tex]\( y \)[/tex]-intercepts for each of the given linear functions are:

1. Slope: [tex]\( 1 \)[/tex]; [tex]\( y \)[/tex]-intercept: [tex]\(-3\)[/tex]
2. Slope: [tex]\( -1 \)[/tex]; [tex]\( y \)[/tex]-intercept: [tex]\( 3 \)[/tex]
3. Slope: [tex]\( -3 \)[/tex]; [tex]\( y \)[/tex]-intercept: [tex]\( 1 \)[/tex]
4. Slope: [tex]\( 3 \)[/tex]; [tex]\( y \)[/tex]-intercept: [tex]\( -1 \)[/tex]