Assume the random variable [tex]x[/tex] is normally distributed with mean [tex]\mu = 89[/tex] and standard deviation [tex]\sigma = 5[/tex]. Find the indicated probability.

[tex]\[ P(x \ \textless \ 87) \][/tex]

[tex]\[ P(x \ \textless \ 87) = \square \][/tex] (Round to four decimal places as needed.)



Answer :

To determine the probability that a normally distributed random variable [tex]\(x\)[/tex] with a mean [tex]\(\mu = 89\)[/tex] and a standard deviation [tex]\(\sigma = 5\)[/tex] takes on a value less than 87, follow these steps:

1. Standardize the Variable:
Convert the value 87 to its corresponding z-score. The z-score measures how many standard deviations a particular value is from the mean.
The formula for the z-score is:
[tex]\[ z = \frac{x - \mu}{\sigma} \][/tex]
Plug in the given values:
[tex]\[ z = \frac{87 - 89}{5} = \frac{-2}{5} = -0.4 \][/tex]

2. Find the Cumulative Probability:
The next step is to find the cumulative probability corresponding to the z-score. This cumulative probability represents the area under the standard normal curve to the left of [tex]\(z = -0.4\)[/tex]. This can be found using standard normal distribution tables, calculators, or software tools.

3. Determine the Probability:
Looking up [tex]\(z = -0.4\)[/tex] in the cumulative distribution function (CDF) table for the standard normal distribution, or utilizing a proper calculator or software, we obtain the cumulative probability.

The cumulative probability corresponding to a z-score of -0.4 is approximately 0.3446.

Thus, the probability that [tex]\(x<87\)[/tex] is:
[tex]\[ P(x < 87) \approx 0.3446 \][/tex]

When rounding to four decimal places, the probability [tex]\(P(x < 87)\)[/tex] is [tex]\(0.3446\)[/tex].