Ms. Wilson recorded the number of students in her homeroom class who participated in spirit week. The table shows the number of students who dressed up each day.

\begin{tabular}{|c|c|c|c|c|c|c|}
\hline Day & Mon. & Tues. & Wed. & Thurs. & Fri. & Total \\
\hline \begin{tabular}{c}
Number of \\
students
\end{tabular} & 0 & 1 & 1 & 3 & 5 & 10 \\
\hline
\end{tabular}

Find the mean and the median of the data set. Determine which of these values is greater.

A. The median, 2, is greater than the mean, 1.
B. The median, 5, is greater than the mean, 0.
C. The mean, 2, is greater than the median, 1.
D. The mean, 5, is greater than the median, 1.



Answer :

Let's go through the data step-by-step and find the mean and the median of the given data set, which shows the number of students who dressed up each day during spirit week:

Days: Monday, Tuesday, Wednesday, Thursday, Friday
Number of Students: 0, 1, 1, 3, 5

1. Calculating the Mean:

The mean is the average of all the numbers. To find the mean, you sum all the values and then divide by the number of values.

To calculate the sum of the number of students:
[tex]\[ 0 + 1 + 1 + 3 + 5 = 10 \][/tex]

Since there are 5 days, the mean is:
[tex]\[ \text{Mean} = \frac{10}{5} = 2.0 \][/tex]

2. Calculating the Median:

The median is the middle value when the numbers are arranged in ascending order. Since the given data set in ascending order is: [tex]\(0, 1, 1, 3, 5\)[/tex]

To find the median, we need to determine the middle number. There are 5 numbers, so the median will be the 3rd number (middle value) in this ordered list:
[tex]\[ 0, 1, 1, 3, 5 \][/tex]
The median is:
[tex]\[ \text{Median} = 1 \][/tex]

3. Comparing the Mean and the Median:

We have:
[tex]\[ \text{Mean} = 2.0 \][/tex]
[tex]\[ \text{Median} = 1 \][/tex]

Clearly, the mean (2.0) is greater than the median (1).

Based on this analysis, the correct choice is:
C. The mean, 2, is greater than the median, 1.