Sure, let's solve this using a proportion.
1. We know that 8 cases of merchandise cost [tex]$60. We are required to find the cost of 12 cases, which is a dozen cases.
2. Let's set up a proportion where we can compare the number of cases to the cost:
\(\frac{\text{Number of Cases}}{\text{Cost}} = \frac{\text{Number of Cases}}{\text{Cost}}\)
3. Plugging in the values we know:
\(\frac{8 \text{ cases}}{60 \text{ dollars}} = \frac{12 \text{ cases}}{x \text{ dollars}}\)
4. To solve for \(x\), we can cross-multiply:
\(8 \times x = 60 \times 12\)
5. Simplifying the right side:
\(8x = 720\)
6. Now, we solve for \(x\) by dividing both sides by 8:
\(x = \frac{720}{8} = 90\)
So, a dozen cases would cost $[/tex]90.
