Instructions: Determine the number of solutions to the given system.

System:
[tex]\[ \left\{
\begin{array}{l}
x = 5 \\
y = (x-5)^2 + 6
\end{array}
\right. \][/tex]

Solution: There are [tex]\(\square\)[/tex] solution(s) to this system.



Answer :

To determine the number of solutions to the given system of equations:
[tex]\[ \left\{\begin{array}{l} x = 5 \\ y = (x - 5)^2 + 6 \end{array}\right. \][/tex]

we need to follow these steps:

1. Substitute the value of [tex]\( x \)[/tex] from the first equation into the second equation:
- The first equation is [tex]\( x = 5 \)[/tex].

2. Calculate the value of [tex]\( y \)[/tex] using the second equation with the substituted value of [tex]\( x \)[/tex]:
[tex]\[ y = (x - 5)^2 + 6 \][/tex]
Substitute [tex]\( x = 5 \)[/tex] into this equation:
[tex]\[ y = (5 - 5)^2 + 6 \][/tex]
Simplify the expression inside the parentheses:
[tex]\[ y = 0^2 + 6 \][/tex]
Further simplify:
[tex]\[ y = 0 + 6 \][/tex]
[tex]\[ y = 6 \][/tex]

3. Identify the solution to the system:
- From the first equation, we know [tex]\( x = 5 \)[/tex].
- From the second equation with the substitution, we have [tex]\( y = 6 \)[/tex].

Therefore, the solution to the system is the ordered pair [tex]\((x, y)\)[/tex]:
[tex]\[ (5, 6) \][/tex]

4. Determine the number of solutions:
- Since we have found one unique pair [tex]\((x, y)\)[/tex] that satisfies both equations, we can conclude that there is exactly one solution for this system.

Hence, the number of solutions to the given system is:

[tex]\[ \boxed{1} \][/tex]