When we react an amine with hydrochloric acid (HCl), the typical outcome is the formation of an ammonium salt. Let's analyze the given reactants and the process step-by-step:
1. Identify the functional groups:
- The compound given is [tex]\( \text{CH}_2-{ \ }^{\circ}-\text{C}-\text{NH}-\text{C}_2\text{H}_5 \)[/tex].
- It contains an amine group [tex]\(\text{-NH}-\text{C}_2\text{H}_5 \)[/tex].
2. Understand the reaction mechanism:
- When amines react with hydrochloric acid (HCl), they gain a proton (H+) from HCl, converting the [tex]\(\text{NH}\)[/tex] group into an ammonium ion ([tex]\(\text{NH}_2^+\)[/tex]).
- As the amine ([tex]\(\text{-NH}-\text{C}_2\text{H}_5\)[/tex]) gains a proton, it becomes [tex]\(\text{-NH}_2^+-\text{C}_2\text{H}_5\)[/tex].
3. Form the ammonium salt:
- Chloride ions from HCl will pair with the newly formed ammonium ion to form an ammonium chloride salt.
- Thus, the product of the reaction involves an ammonium cation and a chloride anion.
4. Write the balanced equation:
- Originally, you have: [tex]\( \text{CH}_2-{ \ }^{\circ}-\text{C}-\text{NH}-\text{C}_2\text{H}_5 + \text{HCl} \)[/tex].
- The amine part ([tex]\(\text{NH}-\text{C}_2\text{H}_5\)[/tex]) will become an ammonium ion ([tex]\(\text{NH}_2^+-\text{C}_2\text{H}_5\)[/tex]), and [tex]\(\text{Cl}^-\)[/tex] will balance it.
- Therefore, the product will be [tex]\( \text{CH}_2-{ \ }^{\circ}-\text{C}-\text{NH}_2^+-\text{C}_2\text{H}_5\text{Cl} \)[/tex], implying the formation of an ammonium salt.
So, the complete reaction is:
[tex]\[ \text{CH}_2-{ \ }^{\circ}-\text{C}-\text{NH}-\text{C}_2\text{H}_5 + \text{HCl} \longrightarrow \text{CH}_2-{ \ }^{\circ}-\text{C}-\text{NH}_2^+-\text{C}_2\text{H}_5\text{Cl} \][/tex]
This represents the formation of an ammonium chloride salt from the reaction of an amine with hydrochloric acid.
