To determine the phenotype ratio for the cross given by the Punnett square, let's analyze the Punnett square step by step.
The Punnett square provided is:
[tex]\[
\begin{array}{|c|c|c|}
\hline & T & t \\
\hline t & Tt & tt \\
\hline t & Tt & tt \\
\hline
\end{array}
\][/tex]
From this Punnett square, we can list the possible genetic combinations of the offspring:
1. From the first column, first row: [tex]\( Tt \)[/tex]
2. From the first column, second row: [tex]\( Tt \)[/tex]
3. From the second column, first row: [tex]\( tt \)[/tex]
4. From the second column, second row: [tex]\( tt \)[/tex]
Counting the genotypes, we have:
- [tex]\( Tt \)[/tex] appears 2 times
- [tex]\( tt \)[/tex] appears 2 times
This genotypic ratio results in the following phenotypes, given that short tails (T) are dominant and long tails (t) are recessive:
- [tex]\( Tt \)[/tex]: Short tails, because the dominant allele [tex]\(T\)[/tex] is present.
- [tex]\( tt \)[/tex]: Long tails, because it has two recessive alleles [tex]\(t\)[/tex].
Now we will count the phenotypes:
- There are 2 instances of [tex]\( Tt \)[/tex] (short tails).
- There are 2 instances of [tex]\( tt \)[/tex] (long tails).
Therefore, the phenotype ratio is:
- Short tails: 2
- Long tails: 2
So, the phenotype ratio for this cross is 2 long tails to 2 short tails. This matches option C:
C. 2 long, 2 short
