To determine which compound is inorganic, we need to analyze the chemical formulas given:
A. [tex]\( \text{C}_6 \text{H}_{12} \text{O}_6 \)[/tex]
B. [tex]\( \text{KH}_2 \text{PO}_4 \)[/tex]
C. [tex]\( \text{CH}_3 \text{COOH} \)[/tex]
D. [tex]\( \text{C}_2 \text{H}_6 \)[/tex]
E. [tex]\( \text{C}_2 \text{H}_5 \text{OH} \)[/tex]
### Step-by-Step Analysis:
1. A. [tex]\( \text{C}_6 \text{H}_{12} \text{O}_6 \)[/tex]: This is glucose. Glucose is a sugar and a well-known organic compound because it contains carbon-hydrogen (C-H) bonds.
2. B. [tex]\( \text{KH}_2 \text{PO}_4 \)[/tex]: This is potassium dihydrogen phosphate. Phosphates are typically considered inorganic compounds, especially salts like potassium dihydrogen phosphate which do not contain carbon-hydrogen (C-H) bonds.
3. C. [tex]\( \text{CH}_3 \text{COOH} \)[/tex]: This is acetic acid. Acetic acid is an organic compound as it contains a carbon backbone and C-H bonds.
4. D. [tex]\( \text{C}_2 \text{H}_6 \)[/tex]: This is ethane. Ethane is an organic compound, composed entirely of carbon and hydrogen atoms.
5. E. [tex]\( \text{C}_2 \text{H}_5 \text{OH} \)[/tex]: This is ethanol. Ethanol is an organic compound because it has C-H bonds and is known as a commonly used alcohol.
### Conclusion:
Based on the analysis, compound [tex]\( \text{KH}_2 \text{PO}_4 \)[/tex] (B) is the only one without carbon-hydrogen bonds and is therefore classified as an inorganic compound.
Thus, the correct answer is:
B. [tex]\( \text{KH}_2 \text{PO}_4 \)[/tex]
