The event of drinking your one cup of coffee black is [tex]$A$[/tex], and the event of drinking your one cup of coffee with milk is [tex]$B$[/tex]. If these events are mutually exclusive, given [tex]$P(A)=0.50$[/tex] and [tex]$P(B)=0.33$[/tex], what is [tex]$P(B \mid A)$[/tex]? Give your answer as an integer or a decimal.

Provide your answer below:
[tex]$\square$[/tex]



Answer :

To find the conditional probability [tex]\( P(B \mid A) \)[/tex], we need to understand what it represents. The conditional probability [tex]\( P(B \mid A) \)[/tex] is the probability that event [tex]\( B \)[/tex] occurs given that event [tex]\( A \)[/tex] has occurred.

First, let's recall that events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are mutually exclusive. This means that they cannot happen simultaneously. Mathematically, for mutually exclusive events, the intersection of [tex]\( A \)[/tex] and [tex]\( B \)[/tex] is zero:

[tex]\[ P(A \cap B) = 0 \][/tex]

According to the formula for conditional probability:

[tex]\[ P(B \mid A) = \frac{P(A \cap B)}{P(A)} \][/tex]

Substituting the values, we have:

[tex]\[ P(B \mid A) = \frac{0}{P(A)} \][/tex]

Since [tex]\( P(A) \)[/tex] is given as 0.50, we substitute this value in:

[tex]\[ P(B \mid A) = \frac{0}{0.50} = 0 \][/tex]

Therefore, the conditional probability [tex]\( P(B \mid A) \)[/tex] is:

[tex]\[ \boxed{0} \][/tex]