The event of sunshine with no clouds is [tex]\(A\)[/tex] and the event of rain is [tex]\(B\)[/tex]. If these events are mutually exclusive events, using [tex]\(P(A)=0.55\)[/tex] and [tex]\(P(B)=0.07\)[/tex], what is [tex]\(P(B \mid A)\)[/tex]?

Provide your answer below:
[tex]\(\square\)[/tex]



Answer :

To find [tex]\( P(B \mid A) \)[/tex], we need to use the definition of conditional probability. The conditional probability of [tex]\( B \)[/tex] given [tex]\( A \)[/tex], denoted as [tex]\( P(B \mid A) \)[/tex], is defined as:

[tex]\[ P(B \mid A) = \frac{P(B \cap A)}{P(A)} \][/tex]

Here, [tex]\( P(B \cap A) \)[/tex] represents the probability that both events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] occur simultaneously. However, since events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are mutually exclusive, they cannot happen at the same time. Therefore, [tex]\( P(B \cap A) = 0 \)[/tex].

Given:
- [tex]\( P(A) = 0.55 \)[/tex]
- [tex]\( P(B) = 0.07 \)[/tex]
- Events [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are mutually exclusive: [tex]\( P(B \cap A) = 0 \)[/tex]

Substituting [tex]\( P(B \cap A) \)[/tex] and [tex]\( P(A) \)[/tex] into the formula for conditional probability:

[tex]\[ P(B \mid A) = \frac{P(B \cap A)}{P(A)} = \frac{0}{0.55} \][/tex]

Since any number divided by a positive number is zero:

[tex]\[ P(B \mid A) = 0 \][/tex]

Thus, the conditional probability [tex]\( P(B \mid A) \)[/tex] is [tex]\( \boxed{0} \)[/tex].