Answer :
To determine the relative frequency for the second class (18-22 hours) as a simplified fraction, follow these steps:
1. Identify the frequency for the second class (18-22 hours):
From the table, the frequency for the second class interval (18-22 hours) is 13.
2. Calculate the total frequency:
Sum the frequencies of all the class intervals:
[tex]\[ 9 + 13 + 12 + 9 + 6 = 49 \][/tex]
Therefore, the total frequency is 49.
3. Calculate the relative frequency for the second class:
The relative frequency is found by dividing the frequency for the second class by the total frequency:
[tex]\[ \text{Relative Frequency} = \frac{\text{Frequency of Second Class}}{\text{Total Frequency}} = \frac{13}{49} \][/tex]
4. Simplify the fraction:
In this specific case, the fraction [tex]\(\frac{13}{49}\)[/tex] is already in its simplest form since 13 and 49 have no common factors other than 1.
Therefore, the relative frequency for the second class (18-22 hours) as a simplified fraction is:
[tex]\[ \boxed{\frac{13}{49}} \][/tex]
1. Identify the frequency for the second class (18-22 hours):
From the table, the frequency for the second class interval (18-22 hours) is 13.
2. Calculate the total frequency:
Sum the frequencies of all the class intervals:
[tex]\[ 9 + 13 + 12 + 9 + 6 = 49 \][/tex]
Therefore, the total frequency is 49.
3. Calculate the relative frequency for the second class:
The relative frequency is found by dividing the frequency for the second class by the total frequency:
[tex]\[ \text{Relative Frequency} = \frac{\text{Frequency of Second Class}}{\text{Total Frequency}} = \frac{13}{49} \][/tex]
4. Simplify the fraction:
In this specific case, the fraction [tex]\(\frac{13}{49}\)[/tex] is already in its simplest form since 13 and 49 have no common factors other than 1.
Therefore, the relative frequency for the second class (18-22 hours) as a simplified fraction is:
[tex]\[ \boxed{\frac{13}{49}} \][/tex]