Consider the following frequency table representing the distribution of hours students study for an exam in a week:

\begin{tabular}{|l|c|}
\hline \multicolumn{2}{|c|}{Hours Students Study for an Exam in a Week} \\
\hline Class & Frequency \\
\hline [tex]$13-17$[/tex] & 9 \\
\hline [tex]$18-22$[/tex] & 13 \\
\hline [tex]$23-27$[/tex] & 12 \\
\hline [tex]$28-32$[/tex] & 9 \\
\hline [tex]$33-37$[/tex] & 6 \\
\hline
\end{tabular}

Determine the relative frequency for the second class as a simplified fraction.



Answer :

To determine the relative frequency for the second class (18-22 hours) as a simplified fraction, follow these steps:

1. Identify the frequency for the second class (18-22 hours):
From the table, the frequency for the second class interval (18-22 hours) is 13.

2. Calculate the total frequency:
Sum the frequencies of all the class intervals:
[tex]\[ 9 + 13 + 12 + 9 + 6 = 49 \][/tex]
Therefore, the total frequency is 49.

3. Calculate the relative frequency for the second class:
The relative frequency is found by dividing the frequency for the second class by the total frequency:
[tex]\[ \text{Relative Frequency} = \frac{\text{Frequency of Second Class}}{\text{Total Frequency}} = \frac{13}{49} \][/tex]

4. Simplify the fraction:
In this specific case, the fraction [tex]\(\frac{13}{49}\)[/tex] is already in its simplest form since 13 and 49 have no common factors other than 1.

Therefore, the relative frequency for the second class (18-22 hours) as a simplified fraction is:

[tex]\[ \boxed{\frac{13}{49}} \][/tex]