Question 1 (Multiple Choice Worth 2 points)

(Rearranging Equations and Formulas LC)

A student is asked to solve the equation [tex]$3v + 16 = 60$[/tex] for [tex]$v$[/tex]. Their work is shown.

\begin{tabular}{|l|r|}
\hline Original Problem & [tex]$3v + 16 = 60$[/tex] \\
\hline Step One & [tex]$\frac{3v}{3} + 16 = \frac{60}{3}$[/tex] \\
\hline Step Two & [tex]$v + 16 = 20$[/tex] \\
\hline Step Three & [tex]$-16 - 16$[/tex] \\
\hline Step Four & [tex]$v = 4$[/tex] \\
\hline
\end{tabular}

The student made a mistake in Step One. What operation should the student have performed?

A. Added 3 to both sides
B. Divided by 16 on both sides
C. Multiplied by 3 on both sides



Answer :

To solve the equation [tex]\(3v + 16 = 60\)[/tex] for [tex]\(v\)[/tex], let's go through the correct steps one by one.

Step 1: Isolate the term with the variable on one side of the equation.
To do this, we need to eliminate the constant term ([tex]\(+16\)[/tex]) on the left-hand side. This can be done by subtracting 16 from both sides of the equation.

[tex]\[ 3v + 16 - 16 = 60 - 16 \][/tex]

Simplifying both sides, we get:

[tex]\[ 3v = 44 \][/tex]

Step 2: Solve for [tex]\(v\)[/tex] by isolating it completely.
Now, we need to divide both sides by the coefficient of [tex]\(v\)[/tex], which is 3.

[tex]\[ \frac{3v}{3} = \frac{44}{3} \][/tex]

This simplifies to:

[tex]\[ v = \frac{44}{3} \][/tex]

Step 3: Verify the solution
It's always a good idea to verify the solution by plugging it back into the original equation to make sure it holds true.

[tex]\[ 3 \left(\frac{44}{3}\right) + 16 = 60 \][/tex]

Simplifying the left-hand side:

[tex]\[ 44 + 16 = 60 \][/tex]

Since both sides of the equation are equal, our solution [tex]\(v = \frac{44}{3}\)[/tex] is correct.

Thus, the student should have subtracted 16 from both sides in the first step.

The correct operation the student should have performed is:
- Subtracted 16 from both sides.