Answer :
To determine the rate at which Greg drove the car, we need to express the number of miles driven as a fraction of the number of hours. This involves placing the miles driven over the hours driven and then reducing the fraction to its simplest form.
1. Assign the given values:
- Miles driven: 213 miles
- Hours driven: 6 hours
2. Express the rate as a fraction:
[tex]\[ \text{Rate} = \frac{\text{Miles driven}}{\text{Hours driven}} = \frac{213}{6} \][/tex]
3. Simplify the fraction:
The greatest common divisor (GCD) of 213 and 6 needs to be found to reduce the fraction. Simplifying, we get:
[tex]\[ \frac{213}{6} = \frac{213 \div 3}{6 \div 3} = \frac{71}{2} \][/tex]
So, the fraction in its simplest form is:
[tex]\[ \frac{71}{2} \][/tex]
Hence, Greg's rate of driving can be expressed as the reduced fraction [tex]\( \frac{71}{2} \)[/tex].
1. Assign the given values:
- Miles driven: 213 miles
- Hours driven: 6 hours
2. Express the rate as a fraction:
[tex]\[ \text{Rate} = \frac{\text{Miles driven}}{\text{Hours driven}} = \frac{213}{6} \][/tex]
3. Simplify the fraction:
The greatest common divisor (GCD) of 213 and 6 needs to be found to reduce the fraction. Simplifying, we get:
[tex]\[ \frac{213}{6} = \frac{213 \div 3}{6 \div 3} = \frac{71}{2} \][/tex]
So, the fraction in its simplest form is:
[tex]\[ \frac{71}{2} \][/tex]
Hence, Greg's rate of driving can be expressed as the reduced fraction [tex]\( \frac{71}{2} \)[/tex].