Simplify the following expression:

[tex]\[ \frac{-70w^2 + 70}{w^2 - 5w + 4} \][/tex]

Simplify your answer as much as possible and keep it completely factored.
Answer: [tex]$\square$[/tex]



Answer :

Let's start with the given expression:

[tex]\[ \frac{-70 w^2 + 70}{w^2 - 5w + 4} \][/tex]

First, consider the numerator and factor it where possible. The numerator is:

[tex]\[ -70 w^2 + 70 \][/tex]

Factor out the common factor of [tex]\( -70 \)[/tex]:

[tex]\[ -70 (w^2 - 1) \][/tex]

Notice that [tex]\( w^2 - 1 \)[/tex] is a difference of squares and can be further factored:

[tex]\[ w^2 - 1 = (w + 1)(w - 1) \][/tex]

Thus, the numerator becomes:

[tex]\[ -70 (w + 1)(w - 1) \][/tex]

Next, consider the denominator:

[tex]\[ w^2 - 5w + 4 \][/tex]

We need to factor this quadratic expression. To do this, look for factors of 4 that add up to -5. The factors -1 and -4 work:

[tex]\[ w^2 - 5w + 4 = (w - 1)(w - 4) \][/tex]

Now we have:

[tex]\[ \frac{-70 (w + 1)(w - 1)}{(w - 1)(w - 4)} \][/tex]

We can cancel the common factor of [tex]\( (w - 1) \)[/tex] in the numerator and the denominator, assuming [tex]\( w \neq 1 \)[/tex]:

[tex]\[ \frac{-70 (w + 1)}{(w - 4)} \][/tex]

Therefore, the completely factored and simplified form of the given expression is:

[tex]\[ \boxed{\frac{-70 (w + 1)}{(w - 4)}} \][/tex]