To find [tex]\[\begin{array}{l}(5+2) \times 7 = (5 \times 7)+(2 \times 7)\end{array}\][/tex], let's go through the steps in detail:
1. Break down the expression:
[tex]\[
(5+2) \times 7
\][/tex]
2. Distribute the multiplication:
[tex]\[
5 \times 7 + 2 \times 7
\][/tex]
3. Calculate each part separately:
[tex]\[
5 \times 7 = 35
\][/tex]
[tex]\[
2 \times 7 = 14
\][/tex]
4. Add the results of each multiplication:
[tex]\[
35 + 14 = 49
\][/tex]
Thus, [tex]\[(5+2) \times 7 = 49\][/tex].
Now, let's follow the same logic for the following expressions:
### For [tex]\[
(4+7) \times 4 = (4 \times 4)+(7 \times 4):
\][/tex]
1. Break down the expression:
[tex]\[
(4+7) \times 4
\][/tex]
2. Distribute the multiplication:
[tex]\[
4 \times 4 + 7 \times 4
\][/tex]
3. Calculate each part separately:
[tex]\[
4 \times 4 = 16
\][/tex]
[tex]\[
7 \times 4 = 28
\][/tex]
4. Add the results of each multiplication:
[tex]\[
16 + 28 = 44
\][/tex]
### For [tex]\[
(5+2) \times 4 = (5 \times 4)+(2 \times 4):
\][/tex]
1. Break down the expression:
[tex]\[
(5+2) \times 4
\][/tex]
2. Distribute the multiplication:
[tex]\[
5 \times 4 + 2 \times 4
\][/tex]
3. Calculate each part separately:
[tex]\[
5 \times 4 = 20
\][/tex]
[tex]\[
2 \times 4 = 8
\][/tex]
4. Add the results of each multiplication:
[tex]\[
20 + 8 = 28
\][/tex]
### For [tex]\[
(2+7) \times 5 = (2 \times 5)+(7 \times 5):
\][/tex]
1. Break down the expression:
[tex]\[
(2+7) \times 5
\][/tex]
2. Distribute the multiplication:
[tex]\[
2 \times 5 + 7 \times 5
\][/tex]
3. Calculate each part separately:
[tex]\[
2 \times 5 = 10
\][/tex]
[tex]\[
7 \times 5 = 35
\][/tex]
4. Add the results of each multiplication:
[tex]\[
10 + 35 = 45
\][/tex]
Thus, we get the following results using the distributive property:
- [tex]\((5+2) \times 7 = 49\)[/tex]
- [tex]\((4+7) \times 4 = 44\)[/tex]
- [tex]\((5+2) \times 4 = 28\)[/tex]
- [tex]\((2+7) \times 5 = 45\)[/tex]
These are the detailed steps to obtain the product using the distributive property for each given expression.
