Six dozen equally priced oranges cost a total of [tex]n[/tex] dollars. In terms of [tex]n[/tex], what is the cost, in cents, of one orange?

A. [tex]\frac{25n}{18}[/tex]
B. [tex]\frac{18n}{15}[/tex]
C. [tex]\frac{n}{72}[/tex]
D. [tex]\frac{72}{n}[/tex]



Answer :

To find the cost of one orange in cents when six dozen equally priced oranges cost a total of [tex]\( n \)[/tex] dollars, follow these steps:

1. Calculate the total number of oranges:
- There are 6 dozen oranges.
- Since there are 12 oranges in a dozen, the total number of oranges is:
[tex]\[ 6 \times 12 = 72 \text{ oranges} \][/tex]

2. Determine the cost of one orange in dollars:
- The total cost for 72 oranges is [tex]\( n \)[/tex] dollars.
- Therefore, the cost for one orange in dollars is:
[tex]\[ \frac{n}{72} \text{ dollars} \][/tex]

3. Convert the cost from dollars to cents:
- There are 100 cents in a dollar.
- To convert the cost from dollars to cents, multiply the cost in dollars by 100:
[tex]\[ \left(\frac{n}{72}\right) \times 100 \][/tex]

4. Simplify the expression:
- Perform the multiplication:
[tex]\[ \frac{n \times 100}{72} = \frac{100n}{72} \][/tex]
- Simplify the fraction:
[tex]\[ \frac{100n}{72} = \frac{25n}{18} \][/tex]

Thus, the cost of one orange in cents is [tex]\(\frac{25n}{18}\)[/tex].

Therefore, the correct answer is:

[tex]\(\boxed{\frac{25n}{18}}\)[/tex]