To find the area of a kite, you can use the formula for the area, which is given by:
[tex]\[ \text{Area} = \frac{1}{2} \times d_1 \times d_2 \][/tex]
where [tex]\( d_1 \)[/tex] and [tex]\( d_2 \)[/tex] are the lengths of the diagonals of the kite.
In this problem, the width of the logo represents one diagonal ([tex]\( d_1 \)[/tex]) and is 12 centimeters, while the height of the logo represents the other diagonal ([tex]\( d_2 \)[/tex]) and is 16 centimeters.
Plugging these values into the formula, you get:
[tex]\[ \text{Area} = \frac{1}{2} \times 12 \, \text{cm} \times 16 \, \text{cm} \][/tex]
[tex]\[ \text{Area} = \frac{1}{2} \times 192 \, \text{cm}^2 \][/tex]
[tex]\[ \text{Area} = 96 \, \text{cm}^2 \][/tex]
Thus, the area of the logo is [tex]\( 96 \, \text{cm}^2 \)[/tex].
So, the correct answer is:
[tex]\[ \boxed{96 \, \text{sq. cm}} \][/tex]
