Sure, let's determine the electron configurations for Silicon (Si) and Yttrium (Y) in noble-gas notation. I will guide you through the process step-by-step.
### Silicon (Si)
1. Determine the atomic number: Silicon has an atomic number of 14.
2. Write out the full electron configuration:
- The first 2 electrons go into the 1s orbital: [tex]\(1s^2\)[/tex]
- The next 2 electrons go into the 2s orbital: [tex]\(2s^2\)[/tex]
- The next 6 electrons fill the 2p orbital: [tex]\(2p^6\)[/tex]
- The next 2 electrons occupy the 3s orbital: [tex]\(3s^2\)[/tex]
- The final 2 electrons go into the 3p orbital: [tex]\(3p^2\)[/tex]
Therefore, the full electron configuration is: [tex]\(1s^2 2s^2 2p^6 3s^2 3p^2\)[/tex]
3. Convert to noble-gas notation:
- The nearest preceding noble gas to silicon is Neon (Ne), which has the electron configuration [tex]\(1s^2 2s^2 2p^6\)[/tex].
- Thus, we can write Silicon's electron configuration in noble-gas notation as: [tex]\([Ne] 3s^2 3p^2\)[/tex]
So, the correct noble-gas notation for Silicon is:
[tex]\[ [Ne] 3s^2 3p^2 \][/tex]
### Yttrium (Y)
1. Determine the atomic number: Yttrium has an atomic number of 39.
2. Write out the full electron configuration:
- The first 2 electrons fill the 1s orbital: [tex]\(1s^2\)[/tex]
- The next 2 electrons fill the 2s orbital: [tex]\(2s^2\)[/tex]
- The next 6 electrons fill the 2p orbital: [tex]\(2p^6\)[/tex]
- The next 2 electrons fill the 3s orbital: [tex]\(3s^2\)[/tex]
- The next 6 electrons fill the 3p orbital: [tex]\(3p^6\)[/tex]
- The next 2 electrons fill the 4s orbital: [tex]\(4s^2\)[/tex]
- The next 10 electrons fill the 3d orbital: [tex]\(3d^{10}\)[/tex]
- The next 6 electrons fill the 4p orbital: [tex]\(4p^6\)[/tex]
- The next 2 electrons fill the 5s orbital: [tex]\(5s^2\)[/tex]
- The final electron goes into the 4d orbital: [tex]\(4d^1\)[/tex]
Therefore, the full electron configuration is:
[tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^1\)[/tex]
3. Convert to noble-gas notation:
- The nearest preceding noble gas to yttrium is Krypton (Kr), which has the electron configuration [tex]\(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6\)[/tex].
- Thus, we can write Yttrium's electron configuration in noble-gas notation as: [tex]\([Kr] 5s^2 4d^1\)[/tex]
So, the correct noble-gas notation for Yttrium is:
[tex]\[ [Kr] 5s^2 4d^1 \][/tex]
If you have any questions or need further clarification, feel free to ask!
