Answer :
Let's analyze each expression and determine whether it is rational or irrational.
### (a) [tex]\(34 + \sqrt{7}\)[/tex]
- Type of numbers involved:
- 34 is a rational number.
- [tex]\(\sqrt{7}\)[/tex] is an irrational number because the square root of a non-perfect square is irrational.
- Rule applied: The sum of a rational and an irrational number is always irrational.
- Conclusion:
- Result: Irrational
- Reason: The sum of a rational and an irrational is always irrational.
### (b) [tex]\(\frac{12}{17} + \frac{4}{21}\)[/tex]
- Type of numbers involved:
- Both [tex]\(\frac{12}{17}\)[/tex] and [tex]\(\frac{4}{21}\)[/tex] are rational numbers because they are ratios of integers.
- Rule applied: The sum of two rational numbers is always rational.
- Conclusion:
- Result: Rational
- Reason: The sum of two rationals is always rational.
### (c) [tex]\(\sqrt{6} \times 23\)[/tex]
- Type of numbers involved:
- [tex]\(\sqrt{6}\)[/tex] is an irrational number because the square root of a non-perfect square is irrational.
- 23 is a rational number.
- Rule applied: The product of a nonzero rational and an irrational number is always irrational.
- Conclusion:
- Result: Irrational
- Reason: The product of a nonzero rational and an irrational is always irrational.
### (d) [tex]\(8 \times \frac{13}{19}\)[/tex]
- Type of numbers involved:
- 8 is a rational number.
- [tex]\(\frac{13}{19}\)[/tex] is also a rational number.
- Rule applied: The product of two rational numbers is always rational.
- Conclusion:
- Result: Rational
- Reason: The product of two rationals is always rational.
### Final Table
[tex]\[ \begin{array}{|c|c|c|} \hline & \begin{array}{l} \text{Result is } \\ \text{Rational} \end{array} & \begin{array}{l} \text{Result is } \\ \text{Irrational} \end{array} \\ \hline (a) \ 34+\sqrt{7} & & \bigcirc \\ \hline (b) \ \frac{12}{17}+\frac{4}{21} & \bigcirc & \\ \hline (c) \ \sqrt{6} \times 23 & & \bigcirc \\ \hline (d) \ 8 \times \frac{13}{19} & \bigcirc & \\ \hline \end{array} \][/tex]
### Reasons Summary:
1. The sum of a rational and an irrational is always irrational.
2. The sum of two rationals is always rational.
3. The product of a nonzero rational and an irrational is always irrational.
4. The product of two rationals is always rational.
### (a) [tex]\(34 + \sqrt{7}\)[/tex]
- Type of numbers involved:
- 34 is a rational number.
- [tex]\(\sqrt{7}\)[/tex] is an irrational number because the square root of a non-perfect square is irrational.
- Rule applied: The sum of a rational and an irrational number is always irrational.
- Conclusion:
- Result: Irrational
- Reason: The sum of a rational and an irrational is always irrational.
### (b) [tex]\(\frac{12}{17} + \frac{4}{21}\)[/tex]
- Type of numbers involved:
- Both [tex]\(\frac{12}{17}\)[/tex] and [tex]\(\frac{4}{21}\)[/tex] are rational numbers because they are ratios of integers.
- Rule applied: The sum of two rational numbers is always rational.
- Conclusion:
- Result: Rational
- Reason: The sum of two rationals is always rational.
### (c) [tex]\(\sqrt{6} \times 23\)[/tex]
- Type of numbers involved:
- [tex]\(\sqrt{6}\)[/tex] is an irrational number because the square root of a non-perfect square is irrational.
- 23 is a rational number.
- Rule applied: The product of a nonzero rational and an irrational number is always irrational.
- Conclusion:
- Result: Irrational
- Reason: The product of a nonzero rational and an irrational is always irrational.
### (d) [tex]\(8 \times \frac{13}{19}\)[/tex]
- Type of numbers involved:
- 8 is a rational number.
- [tex]\(\frac{13}{19}\)[/tex] is also a rational number.
- Rule applied: The product of two rational numbers is always rational.
- Conclusion:
- Result: Rational
- Reason: The product of two rationals is always rational.
### Final Table
[tex]\[ \begin{array}{|c|c|c|} \hline & \begin{array}{l} \text{Result is } \\ \text{Rational} \end{array} & \begin{array}{l} \text{Result is } \\ \text{Irrational} \end{array} \\ \hline (a) \ 34+\sqrt{7} & & \bigcirc \\ \hline (b) \ \frac{12}{17}+\frac{4}{21} & \bigcirc & \\ \hline (c) \ \sqrt{6} \times 23 & & \bigcirc \\ \hline (d) \ 8 \times \frac{13}{19} & \bigcirc & \\ \hline \end{array} \][/tex]
### Reasons Summary:
1. The sum of a rational and an irrational is always irrational.
2. The sum of two rationals is always rational.
3. The product of a nonzero rational and an irrational is always irrational.
4. The product of two rationals is always rational.