Solve for [tex]x[/tex]:

[tex]\[
3x = 6x - 2
\][/tex]




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[tex]$
\begin{array}{c}
\frac{2}{10}+x=\frac{9}{10} \\
x=\frac{[?]}{\square} \quad \begin{array}{l}
\text { Enter the } \\
\text { numerator. }
\end{array}
\end{array}
$[/tex]

Enter the numerator.

Simplify if necessary.
-----

Response:
[tex]\[
\frac{2}{10} + x = \frac{9}{10}
\][/tex]

Solve for [tex]x[/tex]:

[tex]\[
x = \frac{[?]}{\square}
\][/tex]

Enter the numerator.

Simplify if necessary.



Answer :

To solve for [tex]\( x \)[/tex] in the equation [tex]\(\frac{2}{10} + x = \frac{9}{10}\)[/tex], follow these steps:

1. Start with the given equation:
[tex]\[ \frac{2}{10} + x = \frac{9}{10} \][/tex]

2. To isolate [tex]\( x \)[/tex], subtract [tex]\(\frac{2}{10}\)[/tex] from both sides of the equation:
[tex]\[ x = \frac{9}{10} - \frac{2}{10} \][/tex]

3. Perform the subtraction:
[tex]\[ x = \frac{9 - 2}{10} = \frac{7}{10} \][/tex]

Therefore, the numerator of [tex]\( x \)[/tex] in its simplified form is [tex]\( 7 \)[/tex]. So, the numerator is:

[tex]\( 7 \)[/tex]