To find the 2-digit number where [tex]\( p \)[/tex] is the digit in the tens place and 3 is the digit in the ones place, we need to recall how a 2-digit number is formed.
A number is written in the form of [tex]\( 10a + b \)[/tex] where [tex]\( a \)[/tex] is the digit in the tens place and [tex]\( b \)[/tex] is the digit in the ones place.
Given:
- [tex]\( p \)[/tex] is in the tens place
- 3 is in the ones place
Hence, the 2-digit number can be represented as:
[tex]\[ 10p + 3 \][/tex]
Since [tex]\( p \)[/tex] is given as 5, let us plug this value into the equation [tex]\( 10p + 3 \)[/tex]:
[tex]\[ 10(5) + 3 = 50 + 3 = 53 \][/tex]
Therefore, the correct option is:
B. [tex]\( 10p + 3 \)[/tex]
