To determine the stoichiometric coefficients of the balanced chemical reaction:
[tex]\[ 2 KBr + Cl_2 \longrightarrow 2 KCl + Br_2 \][/tex]
1. Identify the reactants and products:
- Reactants: Potassium bromide ([tex]\( \text{KBr} \)[/tex]) and chlorine ([tex]\( \text{Cl}_2 \)[/tex]).
- Products: Potassium chloride ([tex]\( \text{KCl} \)[/tex]) and bromine ([tex]\( \text{Br}_2 \)[/tex]).
2. Balance the equation:
- Potassium (K):
The left side has 2 potassium atoms (from [tex]\(2 \text{KBr}\)[/tex]).
The right side must also have 2 potassium atoms. Hence, we need 2 [tex]\( \text{KCl} \)[/tex] on the right side.
- Bromine (Br):
The left side has 2 bromine atoms (from [tex]\( 2 \text{KBr} \)[/tex]).
The right side has 2 bromine atoms (from [tex]\( \text{Br}_2 \)[/tex]).
The bromine atoms are already balanced.
- Chlorine (Cl):
The left side has 2 chlorine atoms (from [tex]\( \text{Cl}_2 \)[/tex]).
The right side has 2 chlorine atoms (from [tex]\( 2 \text{KCl} \)[/tex]).
The chlorine atoms are already balanced.
The equation is now balanced:
[tex]\[ 2 \text{KBr} + \text{Cl}_2 \rightarrow 2 \text{KCl} + \text{Br}_2 \][/tex]
3. Determine the mole ratios:
- Moles of [tex]\( \text{KBr} \)[/tex]: 2 moles
- Moles of [tex]\( \text{Cl}_2 \)[/tex]: 1 mole
- Moles of [tex]\( \text{KCl} \)[/tex]: 2 moles
- Moles of [tex]\( \text{Br}_2 \)[/tex]: 1 mole
Hence, from the balanced chemical reaction,
[tex]\(( \text{2 moles of KBr}, \text{1 mole of Cl}_2, \text{2 moles of KCl}, \text{1 mole of Br}_2 )\)[/tex]
is the detailed stoichiometric result of the balanced equation.
