A cone is placed inside a cylinder. The cone has half the radius of the cylinder, but the height of each figure is the same. The cone is tilted at an angle so its point touches the edge of the cylinder's base. What is the volume of the space remaining in the cylinder after the cone is placed inside it?

A. [tex]\frac{3}{4} \pi r^2 h[/tex]
B. [tex]\frac{2}{3} \pi r^2 h[/tex]
C. [tex]\frac{11}{12} \pi r^2 h[/tex]
D. [tex]\frac{5}{6} \pi r^2 h[/tex]



Answer :

To solve this problem, let's break it down step-by-step:

1. Define the variables:
Let the radius of the cylinder be [tex]\( r \)[/tex] and the height of the cylinder be [tex]\( h \)[/tex].

2. Determine the dimensions of the cone:
According to the problem, the cone has half the radius of the cylinder and the same height. Therefore, the radius of the cone is [tex]\( \frac{r}{2} \)[/tex] and the height of the cone is [tex]\( h \)[/tex].

3. Calculate the volume of the cylinder:
The volume [tex]\( V_{\text{cylinder}} \)[/tex] of a cylinder is given by the formula:
[tex]\[ V_{\text{cylinder}} = \pi r^2 h \][/tex]

4. Calculate the volume of the cone:
The volume [tex]\( V_{\text{cone}} \)[/tex] of a cone is given by the formula:
[tex]\[ V_{\text{cone}} = \frac{1}{3} \pi r_{\text{cone}}^2 h_{\text{cone}} \][/tex]
Given the radius and height of the cone, we have:
[tex]\[ V_{\text{cone}} = \frac{1}{3} \pi \left( \frac{r}{2} \right)^2 h = \frac{1}{3} \pi \left( \frac{r^2}{4} \right) h = \frac{1}{3} \cdot \frac{1}{4} \pi r^2 h = \frac{1}{12} \pi r^2 h \][/tex]

5. Calculate the remaining volume in the cylinder:
The remaining volume [tex]\( V_{\text{remaining}} \)[/tex] is the volume of the cylinder minus the volume of the cone:
[tex]\[ V_{\text{remaining}} = V_{\text{cylinder}} - V_{\text{cone}} = \pi r^2 h - \frac{1}{12} \pi r^2 h \][/tex]
Simplifying this, we get:
[tex]\[ V_{\text{remaining}} = \left(1 - \frac{1}{12}\right) \pi r^2 h = \left(\frac{12}{12} - \frac{1}{12}\right) \pi r^2 h = \frac{11}{12} \pi r^2 h \][/tex]

Therefore, the volume of the space remaining in the cylinder after the cone is placed inside it is [tex]\( \frac{11}{12} \pi r^2 h \)[/tex].

The correct option is:
[tex]\[ \text{C.} \frac{11}{12} \pi r^2 h \][/tex]