Certainly! Let's solve each question step by step.
Q9. [tex]\(48.75 \div 100\)[/tex]:
To find the result of dividing 48.75 by 100, you simply move the decimal point two places to the left:
[tex]\[ 48.75 \div 100 = 0.4875 \][/tex]
Q10. [tex]\(0.99 \div 1.1\)[/tex]:
Divide 0.99 by 1.1 to get the answer:
[tex]\[ 0.99 \div 1.1 = 0.9 \][/tex]
Q11. The product of two decimals is 131.58. If one of them is 21.5, find the other:
Given:
- The product of two decimals = 131.58
- One of them = 21.5
To find the other number, divide the product by the known number:
[tex]\[ \text{Other number} = \frac{131.58}{21.5} = 6.12 \][/tex]
Q12. A milkman sells 42 litres of milk at rupees 25.50 per litre to a hotel. How much money will he get from them?
Given:
- Volume of milk = 42 litres
- Price per litre = 25.50 rupees
To find the total money received, multiply the volume of milk by the price per litre:
[tex]\[ \text{Total money} = 42 \times 25.50 = 1071 \text{ rupees} \][/tex]
Q13. The thickness of 15 notebooks is 22.5 cm. Find the thickness of one notebook:
Given:
- Total thickness of 15 notebooks = 22.5 cm
- Number of notebooks = 15
To find the thickness of one notebook, divide the total thickness by the number of notebooks:
[tex]\[ \text{Thickness of one notebook} = \frac{22.5}{15} = 1.5 \text{ cm} \][/tex]
Q14. Rohit has 50 rupees. He wants to buy chocolates from that money. If the cost of each chocolate is 7.50 rupees, how many chocolates can he buy?
Given:
- Total money = 50 rupees
- Cost per chocolate = 7.50 rupees
To find the number of chocolates he can buy, divide the total money by the cost per chocolate and use floor division:
[tex]\[ \text{Number of chocolates} = \left\lfloor \frac{50}{7.50} \right\rfloor = 6 \][/tex]
Q15. A postman walks [tex]\(5 \frac{3}{5} \text{ km}\)[/tex] in a day. How much distance will he cover in [tex]\(5 \frac{1}{2}\)[/tex] days?
First, convert the mixed numbers to improper fractions:
- [tex]\(5 \frac{3}{5} = 5 + \frac{3}{5} = 5.6\)[/tex]
- [tex]\(5 \frac{1}{2} = 5 + \frac{1}{2} = 5.5\)[/tex]
Next, multiply the daily distance by the number of days:
[tex]\[ \text{Total distance} = 5.6 \times 5.5 = 30.8 \text{ km} \][/tex]
Q16. What should be added to 5.74 to get 6?
Given:
- Initial value = 5.74
- Target value = 6
To find the required addition, subtract the initial value from the target value:
[tex]\[ 6 - 5.74 = 0.26 \][/tex]
Q17. Find:
(a) [tex]\(2.73 + 1.3\)[/tex]
Add the two numbers:
[tex]\[ 2.73 + 1.3 = 4.03 \][/tex]
(b) [tex]\(11.2 \times 0.15\)[/tex]
Multiply the two numbers:
[tex]\[ 11.2 \times 0.15 = 1.68 \][/tex]
These are the detailed solutions for each of the questions provided.
