Where [tex]$\mu$[/tex] is the magnetic moment in nuclear magnetons and [tex]$j$[/tex] is the nucleon's total angular momentum (or nuclear spin). Then [tex]$g_j$[/tex] is given by

[tex]\[ g_j = g_s \frac{j(j+1) - l(l+1) + s(s+1)}{2 j(j+1)} + g_l \frac{j(j+1) + l(l+1) - s(s+1)}{2 j(j+1)}. \][/tex]

This looks very complicated, but a few moments' study shows that it has a simple repeated structure and two negative signs for which the reader can find a mnemonic to place them in their correct position. You are invited to prove this formula (Problem 8.2).

There is one case in which the formula simplifies considerably: if [tex]$j = l + s$[/tex].



Answer :

The given problem requires proving the formula for the nucleon's gyromagnetic ratio [tex]\( g_j \)[/tex]:

[tex]\[ g_j = g_s \frac{j(j+1)-l(l+1)+s(s+1)}{2j(j+1)} + g_l \frac{j(j+1)+l(l+1)-s(s+1)}{2j(j+1)} \][/tex]

We are provided with the specific case where [tex]\( j = l + s \)[/tex]. By analyzing this, we can see if there is a simplification that occurs under this condition.

Firstly, let's define the quantum numbers involved:
- [tex]\( j \)[/tex] is the total angular momentum,
- [tex]\( l \)[/tex] is the orbital angular momentum, and
- [tex]\( s \)[/tex] is the spin angular momentum.

According to the given values and their relationships, when [tex]\( j = l + s \)[/tex], we use the quantum mechanical relationships for the magnitudes of these angular momenta:

[tex]\[ j^2 = l^2 + s^2 + 2\mathbf{l} \cdot \mathbf{s} \][/tex]

From which we can deduce:

[tex]\[ j(j+1) = l(l+1) + s(s+1) + 2\mathbf{l} \cdot \mathbf{s} \][/tex]

Next, consider the requirement for the magnetic moment formula involving the following terms:

[tex]\[ j(j+1), \quad l(l+1), \quad \text{and}, \quad s(s+1) \][/tex]

Under the condition [tex]\( j = l + s \)[/tex]:

- For term 1:
[tex]\[ j(j+1) - l(l+1) + s(s+1) \rightarrow \text{substitute } j(j+1): \][/tex]
[tex]\[ [l(l+1) + s(s+1) + 2ls] - l(l+1) + s(s+1) = s(s+1) + s(s+1) + 2ls \][/tex]
[tex]\[ = 2s(s+1) + 2\mathbf{l} \cdot \mathbf{s} \][/tex]

- For term 2:
[tex]\[ j(j+1) + l(l+1) - s(s+1) \rightarrow \text{substitute } j(j+1): \][/tex]
[tex]\[ [l(l+1) + s(s+1) + 2\mathbf{l} \cdot \mathbf{s}] + l(l+1) - s(s+1) \][/tex]
[tex]\[ = l(l+1) + l(l+1) + 2\mathbf{l} \cdot \mathbf{s} \][/tex]
[tex]\[ = 2l(l+1) + 2\mathbf{l} \cdot \mathbf{s} \][/tex]

Finally, consolidate these values back into the formula [tex]\( g_j \)[/tex]:

\begin{align}
g_j &= \left( g_s \frac{2\mathbf{s(s+1)} + 2\mathbf{l} \cdot \mathbf{s}}{2j(j+1)} \right) + \left(g_l \frac{2\mathbf{l(l+1)} + 2\mathbf{l} \dot \mathbf{s} }{2j(j+1)} \right)
\end{align
}

Since [tex]\( j(j+1) = l(l+1) + s(s+1) + 2 \mathbf{l} \cdot \mathbf{s} \)[/tex], you can identify part of these values simplifications step-by-step.

We can conclude specific simplifications:
[tex]\[ g_j = \frac{1}{2}(g_l + g_s), \quad \text{if} \quad j = l + s \][/tex]

Thus the formula for [tex]\( g_j \)[/tex] highly depends on the specific [tex]\(j=l+s\)[/tex]. This provides simplicity as

[tex]\[ g_j = \frac{g_l + g_s}{2} \][/tex]

This far simplifies the original formula into manageable factor context and adjustments.