Given a set of ages collected from 11 participants, find the median age. The ages are as follows:

[tex]28, 34, 51, 19, 6, 43, 29, 38, 45, 26, 49, 43[/tex]

(Note: There appears to be a duplicate entry in the set, so ensure to count each number only once while sorting and finding the median.)



Answer :

Let's find the median age of the given participants.

1. List of Ages:
The ages of the participants are:
[tex]\( 28, 34, 51, 19, 6, 43, 29, 38, 45, 26, 49, 43 \)[/tex]

2. Sorting the Ages:
To find the median, the first step is to sort the list of ages in ascending order:
[tex]\( 6, 19, 26, 28, 29, 34, 38, 43, 43, 45, 49, 51 \)[/tex]

3. Counting the Number of Ages:
The number of ages in the list is 12 (even number).

4. Finding the Median:
Since there is an even number of data points, the median will be the average of the two middle numbers in the sorted list. Here, the two middle numbers are the 6th and 7th numbers in the sorted list.

The 6th number is 34, and the 7th number is 38.

[tex]\[ \text{Median} = \frac{34 + 38}{2} = \frac{72}{2} = 36.0 \][/tex]

Therefore, the median age of the participants is 36.0. The sorted list of ages is [tex]\( 6, 19, 26, 28, 29, 34, 38, 43, 43, 45, 49, 51 \)[/tex].