Sure! Let's break down the naming of the coordination compound [tex]\([Co(NH_3)_5Br]SO_4\)[/tex] step-by-step:
1. Identify the components of the coordination compound:
- The coordination sphere is [tex]\([Co(NH_3)_5Br]^2+\)[/tex].
- The counter ion is SO[tex]\(_4\)[/tex], which carries a [tex]\(-2\)[/tex] charge.
2. Determine the charge on the coordination sphere:
- SO[tex]\(_4\)[/tex] (sulfate) has a [tex]\(-2\)[/tex] charge.
- Therefore, the coordination complex must have a [tex]\(+2\)[/tex] charge to balance the [tex]\(-2\)[/tex] charge of the sulfate, making the overall compound neutral.
3. Identify the ligands and their charges:
- NH[tex]\(_3\)[/tex] (ammine) is a neutral ligand.
- Br (bromo) is a monodentate ligand with a [tex]\(-1\)[/tex] charge.
4. Find the oxidation state of the central metal ion (Co):
- Let [tex]\(x\)[/tex] be the oxidation state of cobalt (Co).
- The overall charge of the coordination sphere is [tex]\(+2\)[/tex].
Therefore, we can set up the equation:
[tex]\(x + 5(0) + (-1) = +2\)[/tex]
Simplifying this:
[tex]\(x - 1 = +2\)[/tex]
Solving for [tex]\(x\)[/tex]:
[tex]\(x = +3\)[/tex]
The oxidation state of cobalt (Co) is [tex]\(+3\)[/tex].
5. Name the ligands in alphabetical order:
- NH[tex]\(_3\)[/tex] is named "ammine".
- Br is named "bromo".
6. Add the name of the central metal with its oxidation state in Roman numerals:
- The central metal is cobalt.
- Its oxidation state is [tex]\(+3\)[/tex], which is written as (III).
7. Combine the ligand names, metal name, and oxidation state:
- List the ligands in alphabetical order: "ammine" and "bromo".
- Combine these with the central metal name:
"Pentaamminebromo" (the "penta-" prefix indicates there are five ammine ligands).
8. Include the counter ion:
- The counter ion is sulfate.
Putting it all together, the systematic name of the coordination compound [tex]\([Co(NH_3)_5Br]SO_4\)[/tex] is:
Pentaamminebromocobalt(III) sulfate
