A researcher needs to assign 10 subjects, numbered 0 to 9, to one of two treatment groups: A and B. Use the table of random digits, starting with the first row and first column, to carry out the random assignment.

Table of Random Digits

\begin{tabular}{|l|l|l|l|l|l|l|}
\hline
1 & 07581 & 34728 & 65182 & 58648 & 53252 & 83952 \\
\hline
2 & 23290 & 98227 & 30144 & 83191 & 12167 & 90414 \\
\hline
3 & 79486 & 99776 & 71793 & 95330 & 58256 & 71156 \\
\hline
4 & 46354 & 09077 & 98202 & 03946 & 07455 & 39303 \\
\hline
5 & 00472 & 20787 & 54571 & 73719 & 04368 & 41032 \\
\hline
\end{tabular}

Select the correct random assignment using the table:

A. [tex]$0,7,5,8,1$[/tex] B. [tex]$3,4,7,2,8$[/tex]

A. [tex]$0,2,4,6,8$[/tex] B. [tex]$1,3,5,7,9$[/tex]

A. [tex]$0,3,6,5,8$[/tex] B. [tex]$2,9,1,7,4$[/tex]

A. [tex]$0,7,5,8,1$[/tex] B. [tex]$3,4,2,6,9$[/tex]



Answer :

To carry out the random assignment of the 10 subjects (numbered from 0 to 9) into two groups (A and B), we can use the table of random digits provided.

1. Let's start by considering the sequence of random digits given in the first row and first couple of columns: "07581 34728".

We will use this sequence to assign the subjects to groups A and B.

- The first five digits ("07581") will be assigned to group A.
- The next five digits ("34728") will be assigned to group B.

2. Let's map these digits as follows:
- For Group A, we'll use the first set: 0, 7, 5, 8, 1.
- For Group B, we'll use the second set: 3, 4, 2, 6, 9.

3. The assignment is as follows:
- Group A: 0, 7, 5, 8, 1
- Group B: 3, 4, 2, 6, 9

After reviewing the answer choices:

- A: 0, 7, 5, 8, 1 B: 3, 4, 7, 2, 8
- A: 0, 2, 4, 6, 8 B: 1, 3, 5, 7, 9
- A: 0, 3, 6, 5, 8 B: 2, 9, 1, 7, 4
- A: 0, 7, 5, 8, 1 B: 3, 4, 2, 6, 9

The correct random assignment using the given table of random digits is:

Group A: 0, 7, 5, 8, 1
Group B: 3, 4, 2, 6, 9

Therefore, the correct assignment is the one where:
A: 0, 7, 5, 8, 1
B: 3, 4, 2, 6, 9