Final answer:
The number of different pairs of snacks Ahmed could choose is 6, calculated using the formula for combinations.
Explanation:
The number of different pairs of snacks Ahmed could choose is determined by calculating the number of combinations possible.
- Using the formula for combinations, which is nCr = n! / r!(n-r)!, where n is the total number of items, and r is the number of items to be chosen at a time
- In this case, Ahmed has 4 options for the first snack and 3 options left for the second snack after choosing the first one
- Hence, the number of pairs of snacks Ahmed could choose is 4C2 = 6 different pairs
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