Q1) Order the fractions from lowest to highest.

[tex]\[
\begin{array}{c}
\hline \frac{1}{17}, \frac{1}{19}, \frac{1}{5}, \frac{1}{11} \\
\text{Lowest} \rightarrow \frac{1}{19}, \frac{1}{17}, \frac{1}{11}, \frac{1}{5} \\
\hline
\end{array}
\][/tex]



Answer :

To order the fractions from lowest to highest, let's carefully compare the given fractions:

[tex]\[ \frac{1}{17}, \frac{1}{19}, \frac{1}{5}, \frac{1}{11} \][/tex]

1. Comparing [tex]\(\frac{1}{17}\)[/tex] and [tex]\(\frac{1}{19}\)[/tex]:
- Since the denominators are close, the fraction with the larger denominator is smaller. Hence, [tex]\(\frac{1}{19}\)[/tex] is smaller than [tex]\(\frac{1}{17}\)[/tex].

2. Comparing [tex]\(\frac{1}{5}\)[/tex] and [tex]\(\frac{1}{11}\)[/tex]:
- The denominator 5 is less than 11, making [tex]\(\frac{1}{5}\)[/tex] larger than [tex]\(\frac{1}{11}\)[/tex].

3. Comparing [tex]\(\frac{1}{19}\)[/tex] and [tex]\(\frac{1}{11}\)[/tex]:
- The larger denominator indicates the smaller fraction, thus [tex]\(\frac{1}{19}\)[/tex] is smaller than [tex]\(\frac{1}{11}\)[/tex].

4. Comparing [tex]\(\frac{1}{17}\)[/tex] and [tex]\(\frac{1}{11}\)[/tex]:
- Since 17 is greater than 11, [tex]\(\frac{1}{17}\)[/tex] is smaller than [tex]\(\frac{1}{11}\)[/tex].

5. Comparing [tex]\(\frac{1}{17}\)[/tex] and [tex]\(\frac{1}{5}\)[/tex]:
- Comparing these values, [tex]\(\frac{1}{5}\)[/tex] is larger since the denominator 5 is smaller than 17.

Therefore, arranging the given fractions from the lowest to the highest, we have:

- Lowest:
[tex]\[ \frac{1}{19}=0.0526 \][/tex]
- Next lowest:
[tex]\[ \frac{1}{17}=0.0588 \][/tex]
- Next:
[tex]\[ \frac{1}{11}=0.0909 \][/tex]
- Highest:
[tex]\[ \frac{1}{5}=0.2 \][/tex]

Thus, ordering the original fractions from lowest to highest:

[tex]\[ \frac{1}{19}, \frac{1}{17}, \frac{1}{11}, \frac{1}{5} \][/tex]