Write the names of the given compounds and calculate their molecular weight.

(i) [tex]AlCl_3[/tex]

(ii) [tex]CaCO_3[/tex]

(iii) [tex]NH_4OH[/tex]

(iv) [tex]MgCl_2[/tex]

(v) [tex]Ca(HCO_3)_2[/tex]

(vi) [tex]AlPO_4[/tex]

(vii) [tex]Mg_3(PO_4)_2[/tex]

(viii) [tex]H_2CO_3[/tex]



Answer :

Sure, let's go through each compound one by one, provide their names, and calculate their molecular weights step by step:

1. [tex]\( \text{AlCl}_3 \)[/tex] (Aluminum Chloride)
- This compound consists of 1 Aluminum (Al) atom and 3 Chlorine (Cl) atoms.
- The molecular weight is calculated as follows:
- 1 Al × 26.98 (atomic weight of Al) + 3 Cl × 35.45 (atomic weight of Cl).
- Therefore, the molecular weight of [tex]\( \text{AlCl}_3 \)[/tex] is 133.33 g/mol.

2. [tex]\( \text{MgCl}_2 \)[/tex] (Magnesium Chloride)
- This compound consists of 1 Magnesium (Mg) atom and 2 Chlorine (Cl) atoms.
- The molecular weight is calculated as follows:
- 1 Mg × 24.305 (atomic weight of Mg) + 2 Cl × 35.45 (atomic weight of Cl).
- Therefore, the molecular weight of [tex]\( \text{MgCl}_2 \)[/tex] is 95.205 g/mol.

3. [tex]\( \text{Mg}_3( \text{PO}_4)_2 \)[/tex] (Magnesium Phosphate)
- This compound consists of 3 Magnesium (Mg) atoms, 2 Phosphorus (P) atoms, and 8 Oxygen (O) atoms.
- The molecular weight is calculated as follows:
- 3 Mg × 24.305 (atomic weight of Mg) + 2 P × 30.97 (atomic weight of P) + 8 O × 16.00 (atomic weight of O).
- Therefore, the molecular weight of [tex]\( \text{Mg}_3( \text{PO}_4)_2 \)[/tex] is 262.855 g/mol.

4. [tex]\( \text{CaCO}_3 \)[/tex] (Calcium Carbonate)
- This compound consists of 1 Calcium (Ca) atom, 1 Carbon (C) atom, and 3 Oxygen (O) atoms.
- The molecular weight is calculated as follows:
- 1 Ca × 40.08 (atomic weight of Ca) + 1 C × 12.01 (atomic weight of C) + 3 O × 16.00 (atomic weight of O).
- Therefore, the molecular weight of [tex]\( \text{CaCO}_3 \)[/tex] is 100.09 g/mol.

5. [tex]\( \text{Ca}( \text{HCO}_3)_2 \)[/tex] (Calcium Bicarbonate)
- This compound consists of 1 Calcium (Ca) atom, 2 Hydrogen (H) atoms, 2 Carbon (C) atoms, and 6 Oxygen (O) atoms.
- The molecular weight is calculated as follows:
- 1 Ca × 40.08 (atomic weight of Ca) + 2 H × 1.008 (atomic weight of H) + 2 C × 12.01 (atomic weight of C) + 6 O × 16.00 (atomic weight of O).
- Therefore, the molecular weight of [tex]\( \text{Ca}( \text{HCO}_3)_2 \)[/tex] is 162.116 g/mol.

6. [tex]\( \text{H}_2\text{CO}_3 \)[/tex] (Carbonic Acid)
- This compound consists of 2 Hydrogen (H) atoms, 1 Carbon (C) atom, and 3 Oxygen (O) atoms.
- The molecular weight is calculated as follows:
- 2 H × 1.008 (atomic weight of H) + 1 C × 12.01 (atomic weight of C) + 3 O × 16.00 (atomic weight of O).
- Therefore, the molecular weight of [tex]\( \text{H}_2\text{CO}_3 \)[/tex] is 62.026 g/mol.

7. [tex]\( \text{NH}_4\text{OH} \)[/tex] (Ammonium Hydroxide)
- This compound consists of 1 Nitrogen (N) atom, 5 Hydrogen (H) atoms, and 1 Oxygen (O) atom.
- The molecular weight is calculated as follows:
- 1 N × 14.01 (atomic weight of N) + 5 H × 1.008 (atomic weight of H) + 1 O × 16.00 (atomic weight of O).
- Therefore, the molecular weight of [tex]\( \text{NH}_4\text{OH} \)[/tex] is 35.05 g/mol.

8. [tex]\( \text{AlPO}_4 \)[/tex] (Aluminum Phosphate)
- This compound consists of 1 Aluminum (Al) atom, 1 Phosphorus (P) atom, and 4 Oxygen (O) atoms.
- The molecular weight is calculated as follows:
- 1 Al × 26.98 (atomic weight of Al) + 1 P × 30.97 (atomic weight of P) + 4 O × 16.00 (atomic weight of O).
- Therefore, the molecular weight of [tex]\( \text{AlPO}_4 \)[/tex] is 121.95 g/mol.

To summarize, the molecular weights of the given compounds are:
- [tex]\( \text{AlCl}_3 \)[/tex]: 133.33 g/mol
- [tex]\( \text{MgCl}_2 \)[/tex]: 95.205 g/mol
- [tex]\( \text{Mg}_3( \text{PO}_4)_2 \)[/tex]: 262.855 g/mol
- [tex]\( \text{CaCO}_3 \)[/tex]: 100.09 g/mol
- [tex]\( \text{Ca}( \text{HCO}_3)_2 \)[/tex]: 162.116 g/mol
- [tex]\( \text{H}_2\text{CO}_3 \)[/tex]: 62.026 g/mol
- [tex]\( \text{NH}_4\text{OH} \)[/tex]: 35.05 g/mol
- [tex]\( \text{AlPO}_4 \)[/tex]: 121.95 g/mol