Let's go through the table step by step and complete the required answers for fields labeled 7.1 to 7.4.
### 1. Water Reabsorbed
- Quantity passing into C: [tex]\( 180 \ \text{dm}^3 \)[/tex]
- Quantity passing through H: [tex]\( 1.5 \ \text{dm}^3 \)[/tex]
- Quantity reabsorbed: [tex]\( 178.5 \ \text{dm}^3 \)[/tex]
To find the percentage reabsorbed:
[tex]\[ \text{Percentage reabsorbed} = \left( \frac{\text{Quantity reabsorbed}}{\text{Quantity passing into C}} \right) \times 100 \][/tex]
[tex]\[ \text{Percentage reabsorbed} = \left( \frac{178.5}{180} \right) \times 100 = 99.167\% \][/tex]
So, (7.1) = 99.167
### 2. Glucose
- Quantity passing into C: [tex]\( 180 \ \text{g} \)[/tex]
- Quantity passing through H: (7.2)
- Quantity reabsorbed: [tex]\( 180 \ \text{g} \)[/tex]
- Percentage reabsorbed: [tex]\( 100\% \)[/tex]
Since all glucose is reabsorbed, none passes through:
[tex]\[ \text{Quantity passing through H} = 0 \ \text{g} \][/tex]
So, (7.2) = 0
### 3. Urea
- Quantity passing into C: [tex]\( 53 \ \text{g} \)[/tex]
- Quantity passing through H: [tex]\( 25 \ \text{g} \)[/tex]
- Quantity reabsorbed: (7.3)
To find the quantity reabsorbed:
[tex]\[ \text{Quantity reabsorbed} = \text{Quantity passing into C} - \text{Quantity passing through H} \][/tex]
[tex]\[ \text{Quantity reabsorbed} = 53 \ \text{g} - 25 \ \text{g} = 28 \ \text{g} \][/tex]
So, (7.3) = 28
### 4. Urea Percentage Reabsorbed
- Quantity passing into C: [tex]\( 53 \ \text{g} \)[/tex]
- Quantity passing through H: [tex]\( 25 \ \text{g} \)[/tex]
- Quantity reabsorbed: [tex]\( 28 \ \text{g} \)[/tex]
To find the percentage reabsorbed:
[tex]\[ \text{Percentage reabsorbed} = \left( \frac{\text{Quantity reabsorbed}}{\text{Quantity passing into C}} \right) \times 100 \][/tex]
[tex]\[ \text{Percentage reabsorbed} = \left( \frac{28}{53} \right) \times 100 \approx 52.83\% \][/tex]
So, (7.4) = 52.83
### Completed Table:
\begin{tabular}{|l|c|c|c|c|}
\hline Substance & \begin{tabular}{l}
Quantity \\
passing \\
into C
\end{tabular} & \begin{tabular}{l}
Quantity \\
passing \\
through H
\end{tabular} & \begin{tabular}{l}
Quantity \\
reabsorbed
\end{tabular} & \begin{tabular}{l}
Percentage \\
reabsorbed
\end{tabular} \\
\hline water & [tex]$180 \ \text{dm}^3$[/tex] & [tex]$1.5 \ \text{dm}^3$[/tex] & [tex]$178.5 \ \text{dm}^3$[/tex] & 99.167 \% \\
\hline glucose & 180 g & 0 & 180 g & 100 \% \\
\hline urea & 53 g & 25 g & 28 g & 52.83 \% \\
\hline
\end{tabular}
