What is the mass of [tex]6.45 \times 10^{25}[/tex] atoms of Cu?

Given:
- Molar mass of Cu = [tex]63.55 \, \text{g/mol}[/tex]
- [tex]1 \, \text{mol} = 6.02 \times 10^{23}[/tex] atoms

A. 1.69 g Cu
B. [tex]6810 \, \text{g Cu}[/tex]
C. [tex]2.47 \times 10^{5} \, \text{g Cu}[/tex]
D. 107 g Cu



Answer :

To find the mass of [tex]\( 6.45 \times 10^{25} \)[/tex] atoms of copper (Cu), we need to follow these steps:

1. Determine the number of moles of Cu:
- Given the number of atoms: [tex]\( 6.45 \times 10^{25} \)[/tex]
- Avogadro's number, which is the number of atoms in one mole: [tex]\( 6.02 \times 10^{23} \)[/tex]

To find the number of moles ([tex]\( n \)[/tex]), divide the number of atoms by Avogadro's number:
[tex]\[ n = \frac{6.45 \times 10^{25}}{6.02 \times 10^{23}} \][/tex]
[tex]\[ n \approx 107.14285714285717 \text{ moles} \][/tex]

2. Calculate the mass of Cu:
- Number of moles obtained: [tex]\( 107.14285714285717 \text{ moles} \)[/tex]
- Molar mass of Cu: [tex]\( 63.55 \text{ g/mol} \)[/tex]

To find the mass, multiply the number of moles by the molar mass:
[tex]\[ \text{Mass of Cu} = 107.14285714285717 \text{ moles} \times 63.55 \text{ g/mol} \][/tex]
[tex]\[ \text{Mass of Cu} \approx 6808.9285714285725 \text{ g} \][/tex]

Therefore, the mass of [tex]\( 6.45 \times 10^{25} \)[/tex] atoms of copper is approximately [tex]\( 6808.93 \)[/tex] grams.

So the correct answer is B. [tex]\( 6,810 \text{ g Cu} \)[/tex].