The wind speed near the center of a tornado is represented by the equation [tex]S = 93 \log d + 65[/tex], where [tex]d[/tex] is the distance, in miles, that the tornado travels and [tex]S[/tex] is the wind speed, in miles per hour.

If the wind speed was 150 miles per hour, how many miles did the tornado travel? Round your answer to the nearest tenth.

Provide your answer below:



Answer :

To find the distance [tex]\(d\)[/tex] that the tornado has traveled when the wind speed [tex]\(S\)[/tex] is 150 miles per hour, we start with the given equation:

[tex]\[ S = 93 \log_{10}(d) + 65 \][/tex]

We are given [tex]\( S = 150 \)[/tex]. Plugging it into the equation, we get:

[tex]\[ 150 = 93 \log_{10}(d) + 65 \][/tex]

First, we isolate the logarithmic term by subtracting 65 from both sides:

[tex]\[ 150 - 65 = 93 \log_{10}(d) \][/tex]

This simplifies to:

[tex]\[ 85 = 93 \log_{10}(d) \][/tex]

Next, we solve for [tex]\( \log_{10}(d) \)[/tex] by dividing both sides by 93:

[tex]\[ \log_{10}(d) = \frac{85}{93} \][/tex]

Evaluating the right-hand side, we find:

[tex]\[ \log_{10}(d) \approx 0.9139784946236559 \][/tex]

To solve for [tex]\(d\)[/tex], we need to exponentiate both sides with base 10:

[tex]\[ d = 10^{0.9139784946236559} \][/tex]

Calculating the value, we get:

[tex]\[ d \approx 8.203109232014354 \][/tex]

Finally, we round this distance to the nearest tenth:

[tex]\[ d \approx 8.2 \][/tex]

Thus, the tornado traveled approximately [tex]\( \boxed{8.2} \)[/tex] miles.