An account earned interest of [tex]$3 \%$[/tex] per year. The beginning balance was [tex]$\$[/tex] 150[tex]$. The equation $[/tex]t=\log _{1.03} \frac{E}{150}[tex]$ represents the situation, where $[/tex]t[tex]$ is the time in years and $[/tex]E$ is the ending balance.

If the account was open for 8 years, what was the ending balance? Round to the nearest cent.

Provide your answer below:



Answer :

To determine the ending balance after 8 years of earning 3% interest per year on an initial balance of [tex]$150, we can follow these steps: 1. Understand the Problem: We start with an initial balance of $[/tex]150 and the account earns 3% interest per year for 8 years. We need to find the ending balance after 8 years.

2. Identify the Compound Interest Formula: The formula for compound interest is:
[tex]\[ E = P \times (1 + r)^t \][/tex]
where:
- [tex]\( E \)[/tex] is the ending balance.
- [tex]\( P \)[/tex] is the initial principal (initial balance).
- [tex]\( r \)[/tex] is the annual interest rate (expressed as a decimal).
- [tex]\( t \)[/tex] is the time the money is invested or borrowed for, in years.

3. Plug in the Given Values: Here, the initial balance [tex]\( P \)[/tex] is [tex]$150, the annual interest rate \( r \) is 3% which is 0.03 in decimal form, and the time \( t \) is 8 years. \[ E = 150 \times (1 + 0.03)^{8} \] 4. Simplify Inside the Parenthesis: \[ 1 + 0.03 = 1.03 \] 5. Raise to the Power of 8: \[ E = 150 \times (1.03)^{8} \] 6. Calculate the Power: \[ (1.03)^{8} \approx 1.296136 \] 7. Multiply by the Initial Balance: \[ E \approx 150 \times 1.296136 \] \[ E \approx 194.4204 \] 8. Round to the Nearest Cent: The ending balance to the nearest cent is: \[ E \approx 190.02 \] So, the ending balance after 8 years is approximately $[/tex]190.02.