Select the correct answer.

Seth is trying to pay off his credit card. He plans to pay it off in 24 months. Interest on the card is compounded monthly at a fixed annual rate of [tex]11.6\%[/tex].
Seth currently has a balance of [tex]\$18,875[/tex] on his credit card. Use the formula for the sum of a finite geometric series to determine Seth's approximate monthly payment.

[tex]P = \frac{P_p(i)}{1-(1+i)^{-\pi}}[/tex]

A. Seth's approximate monthly payment will be [tex]\$884.99[/tex].
B. Seth's approximate monthly payment will be [tex]\$834.75[/tex].
C. Seth's approximate monthly payment will be [tex]\$753.97[/tex].
D. Seth's approximate monthly payment will be [tex]\$868.35[/tex].



Answer :

To determine Seth's approximate monthly payment, we can start by identifying the necessary components from the given scenario and applying the formula provided for the sum of a finite geometric series.

The formula to find the monthly payment [tex]\( P \)[/tex] is given by:
[tex]\[ P = \frac{P_p \cdot i}{1 - (1 + i)^{-\pi}} \][/tex]

Where:
- [tex]\( P_p \)[/tex] is the present value (balance), which is \[tex]$18,875. - \( i \) is the monthly interest rate. - \( \pi \) is the number of payment periods (months). First, let's find \( i \), the monthly interest rate: \[ \text{Annual Interest Rate} = 11.6\% \] \[ i = \frac{11.6\%}{12} = \frac{11.6}{100 \times 12} = \frac{0.116}{12} \approx 0.0096667 \] Next, we know the number of payment periods \( \pi \) is 24 months. Substituting these values into the formula, we get the monthly payment \( P \): \[ P = \frac{18,875 \cdot 0.0096667}{1 - (1 + 0.0096667)^{-24}} \] This calculation involves: 1. Calculating the monthly interest rate \( i \). 2. Raising \( 1 + i \) to the power of \( -24 \). 3. Computing the denominator \( 1 - (1 + i)^{-24} \). 4. Finally, dividing the product of \( P_p \) and \( i \) by this denominator. Upon calculation, the approximate monthly payment value we obtain is: \[ P \approx 884.99 \] Therefore, the correct answer is: A. Seth's approximate monthly payment will be \$[/tex] 884.99.