Answered

Label A-F based on the table using C for concentrated and D for dilute.

A [tex]$\square$[/tex]
B [tex]$\square$[/tex]
C [tex]$\square$[/tex]
D [tex]$\square$[/tex]
E [tex]$\square$[/tex]
F [tex]$\square$[/tex]

\begin{tabular}{|c|c|c|}
\hline \begin{tabular}{l}
Acid/Base \\
\end{tabular} & Molarity & \begin{tabular}{l}
Concentrated / \\
Dilute
\end{tabular} \\
\hline \multirow{2}{}{HCl} & 12 M & A \\
\hline & 0.5 M & B \\
\hline \multirow{2}{}{NaOH} & 0.01 M & C \\
\hline & 6.0 M & D \\
\hline \multirow{2}{*}{[tex]$H_2SO_4$[/tex]} & 0.05 M & E \\
\hline & 10 M & F \\
\hline
\end{tabular}



Answer :

GinnyAnswer
Let's classify each solution as concentrated (C) or dilute (D) based on their molarity.

1. A (HCl with 12 M)
- 12 M HCl is considered concentrated. So, A should be labeled as C.

2. B (HCl with 0.5 M)
- 0.5 M HCl is considered dilute. So, B should be labeled as D.

3. C (NaOH with 0.01 M)
- 0.01 M NaOH is considered dilute. So, C should be labeled as D.

4. D (NaOH with 6.0 M)
- 6.0 M NaOH is considered concentrated. So, D should be labeled as C.

5. E (H[tex]\(_2\)[/tex]SO[tex]\(_4\)[/tex] with 0.05 M)
- 0.05 M H[tex]\(_2\)[/tex]SO[tex]\(_4\)[/tex] is considered dilute. So, E should be labeled as D.

6. F (H[tex]\(_2\)[/tex]SO[tex]\(_4\)[/tex] with 10 M)
- 10 M H[tex]\(_2\)[/tex]SO[tex]\(_4\)[/tex] is considered concentrated. So, F should be labeled as C.

Summarizing, the labels should be:
- A: C
- B: D
- C: D
- D: C
- E: D
- F: C