Let’s walk through the step-by-step execution of the provided C++ code to determine its output:
1. Initialization:
- An integer `n` is declared.
2. For Loop:
- The for loop initializes `n` to 5.
- The loop will execute as long as `n` is greater than 0.
- After each iteration, `n` will be decremented by 1.
3. First Iteration (n = 5):
- `n` is 5.
- The condition `if (n==3)` is checked, but `n` is not 3, so the loop continues.
4. Second Iteration (n = 4):
- `n` is 4.
- The condition `if (n==3)` is checked, but `n` is still not 3, so the loop continues.
5. Third Iteration (n = 3):
- `n` is 3.
- The condition `if (n==3)` is checked, and `n` equals 3 this time.
- As the condition is true, the `break` statement is executed, which causes an immediate exit from the loop.
6. Loop Exit:
- The loop exits when `n` reaches 3 due to the `break` statement.
Given this step-by-step explanation, the output will be the value of `n` when the loop is exited, which is `3`.
Therefore, the output of the code is:
```
3
```
