Solve for [tex]\( x \)[/tex].

[tex]\[ 3x = 6x - 2 \][/tex]



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[tex]\[2x \ \textless \ -x + 20\][/tex]
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Response:
Solve the inequality for [tex]\( x \)[/tex].

[tex]\[ 2x \ \textless \ -x + 20 \][/tex]



Answer :

Sure, let's solve the inequality [tex]\(2x < -x + 20\)[/tex] step by step.

1. Isolate the variable x on one side:
To begin, we want to move all terms involving [tex]\(x\)[/tex] to the same side of the inequality. Currently, the inequality is:

[tex]\[ 2x < -x + 20 \][/tex]

To do this, add [tex]\(x\)[/tex] to both sides of the inequality:

[tex]\[ 2x + x < -x + x + 20 \][/tex]

Simplifying this, we get:

[tex]\[ 3x < 20 \][/tex]

2. Solve for x:
Now we need to isolate [tex]\(x\)[/tex] by dividing both sides of the inequality by 3:

[tex]\[ x < \frac{20}{3} \][/tex]

Simplifying the fraction:

[tex]\[ x < 6.67 \][/tex]

So, the solution to the inequality [tex]\(2x < -x + 20\)[/tex] is:

[tex]\[ x < 6.67 \][/tex]