To find the mass of 10.0 moles of CH₂O₂, we must first determine the molar mass of CH₂O₂. This involves adding the atomic masses of all the atoms in the molecular formula CH₂O₂.
Here’s how we can proceed:
1. Calculate the molar mass of CH₂O₂:
- Carbon (C) has an atomic mass of 12.01 g/mol.
- Hydrogen (H) has an atomic mass of 1.01 g/mol. There are 2 hydrogen atoms, so [tex]\( 2 \times 1.01 \)[/tex].
- Oxygen (O) has an atomic mass of 16.00 g/mol. There are 2 oxygen atoms, so [tex]\( 2 \times 16.00 \)[/tex].
Adding these together:
[tex]\[
\text{Molar mass of } CH₂O₂ = 12.01 + (2 \times 1.01) + (2 \times 16.00) = 12.01 + 2.02 + 32.00 = 46.03 \text{ g/mol}
\][/tex]
2. Using the molar mass to find the mass of 10.0 moles of CH₂O₂:
- We know that 1 mole of CH₂O₂ is 46.03 grams.
- Therefore, to find the mass of 10.0 moles of CH₂O₂, we simply multiply the molar mass by the number of moles:
[tex]\[
\text{Mass} = \text{Number of moles} \times \text{Molar mass}
\][/tex]
[tex]\[
\text{Mass} = 10.0 \text{ moles} \times 46.03 \text{ g/mol} = 460.3 \text{ grams}
\][/tex]
So, the mass of 10.0 moles of CH₂O₂ is 460.3 grams.
Now, considering the options provided, the correct choice for the green box, which is the conversion factor we’re using, should be:
3. 46.03 g CH₂O₂
This is because the conversion factor directly relates the amount in moles to the corresponding mass in grams, which is the molar mass of CH₂O₂.
