Certainly! Let’s walk through the calculation step-by-step to determine how many moles of aluminum sulfide (Al₂S₃) are equivalent to 605 grams of Al₂S₃, given that the molar mass of Al₂S₃ is 150.17 g/mol.
### Step 1: Identify the given values
- The mass of Al₂S₃: [tex]\( 605 \)[/tex] grams.
- The molar mass of Al₂S₃: [tex]\( 150.17 \)[/tex] grams per mole (g/mol).
### Step 2: Use the formula for calculating moles
The formula to find the number of moles ([tex]\( n \)[/tex]) is:
[tex]\[ n = \frac{\text{mass}}{\text{molar mass}} \][/tex]
Where:
- [tex]\( \text{mass} \)[/tex] is the mass of the compound in grams.
- [tex]\( \text{molar mass} \)[/tex] is the molar mass of the compound in grams per mole.
### Step 3: Plug in the given values
Substitute the given mass of Al₂S₃ and its molar mass into the formula:
[tex]\[ n = \frac{605 \, \text{g}}{150.17 \, \text{g/mol}} \][/tex]
### Step 4: Calculate the number of moles
Perform the division:
[tex]\[ n = \frac{605}{150.17} \approx 4.028767396950124 \, \text{moles} \][/tex]
### Conclusion
Therefore, 605 grams of Al₂S₃ is equivalent to approximately [tex]\( 4.02877 \)[/tex] moles of Al₂S₃.
