A population numbers 16,000 organisms initially and decreases by [tex]$8.9\%$[/tex] each year. Suppose [tex]$P$[/tex] represents the population, and [tex]$t$[/tex] the number of years. An exponential model for the population can be written in the form [tex]$P = a \cdot b^t$[/tex].

Given this model, determine the values of [tex]$a$[/tex] and [tex]$b$[/tex].

[tex]\[ P = \][/tex]
[tex]\[ \square \][/tex]



Answer :

To model the population decrease over time, we need to use the exponential decay formula, which is given by:

[tex]\[ P = a \cdot b^t \][/tex]

where:
- [tex]\( P \)[/tex] is the population at time [tex]\( t \)[/tex].
- [tex]\( a \)[/tex] is the initial population.
- [tex]\( b \)[/tex] is the base of the exponential, which represents the factor by which the population decreases each year.
- [tex]\( t \)[/tex] is the time in years.

Let's go through the steps to determine the values of [tex]\( a \)[/tex] and [tex]\( b \)[/tex]:

1. Initial Population ([tex]\( a \)[/tex]): The problem states that the initial population is 16,000 organisms. Therefore,

[tex]\[ a = 16000 \][/tex]

2. Annual Decrease Rate: The population decreases by 8.9% each year. To find [tex]\( b \)[/tex], we need to understand that the population retains a percentage of its value after each year. If it decreases by 8.9%, it retains [tex]\( 100\% - 8.9\% = 91.1\% \)[/tex] of its population each year.

To express this as a decimal:

[tex]\[ \text{Retained population} = 91.1\% = 0.911 \][/tex]

Therefore,

[tex]\[ b = 0.911 \][/tex]

Combining these values into our exponential model, we have:

[tex]\[ P = 16000 \cdot 0.911^t \][/tex]