To determine which compounds have the empirical formula [tex]\( CH_2O \)[/tex], we need to simplify the molecular formulas given to see if they match [tex]\( CH_2O \)[/tex].
### Steps to Check Each Compound:
1. For [tex]\( C_2H_4O_2 \)[/tex]:
- Given: [tex]\( C = 2 \)[/tex], [tex]\( H = 4 \)[/tex], [tex]\( O = 2 \)[/tex]
- Simplify the ratio of the elements:
- Carbon: [tex]\( 2 / 2 = 1 \)[/tex]
- Hydrogen: [tex]\( 4 / 2 = 2 \)[/tex]
- Oxygen: [tex]\( 2 / 2 = 1 \)[/tex]
- Resulting formula: [tex]\( CH_2O \)[/tex]
- Conclusion: Yes, it matches [tex]\( CH_2O \)[/tex].
2. For [tex]\( C_3H_6O_3 \)[/tex]:
- Given: [tex]\( C = 3 \)[/tex], [tex]\( H = 6 \)[/tex], [tex]\( O = 3 \)[/tex]
- Simplify the ratio of the elements:
- Carbon: [tex]\( 3 / 3 = 1 \)[/tex]
- Hydrogen: [tex]\( 6 / 3 = 2 \)[/tex]
- Oxygen: [tex]\( 3 / 3 = 1 \)[/tex]
- Resulting formula: [tex]\( CH_2O \)[/tex]
- Conclusion: Yes, it matches [tex]\( CH_2O \)[/tex].
3. For [tex]\( CH_2O_2 \)[/tex]:
- Given: [tex]\( C = 1 \)[/tex], [tex]\( H = 2 \)[/tex], [tex]\( O = 2 \)[/tex]
- Simplify the ratio of the elements:
- Carbon: [tex]\( 1 / 1 = 1 \)[/tex]
- Hydrogen: [tex]\( 2 / 1 = 2 \)[/tex]
- Oxygen: [tex]\( 2 / 1 = 2 \)[/tex]
- Resulting formula: [tex]\( CH_2O_2 \)[/tex]
- Conclusion: No, it does not match [tex]\( CH_2O \)[/tex].
4. For [tex]\( C_5H_{10}O_5 \)[/tex]:
- Given: [tex]\( C = 5 \)[/tex], [tex]\( H = 10 \)[/tex], [tex]\( O = 5 \)[/tex]
- Simplify the ratio of the elements:
- Carbon: [tex]\( 5 / 5 = 1 \)[/tex]
- Hydrogen: [tex]\( 10 / 5 = 2 \)[/tex]
- Oxygen: [tex]\( 5 / 5 = 1 \)[/tex]
- Resulting formula: [tex]\( CH_2O \)[/tex]
- Conclusion: Yes, it matches [tex]\( CH_2O \)[/tex].
5. For [tex]\( C_6H_{12}O_6 \)[/tex]:
- Given: [tex]\( C = 6 \)[/tex], [tex]\( H = 12 \)[/tex], [tex]\( O = 6 \)[/tex]
- Simplify the ratio of the elements:
- Carbon: [tex]\( 6 / 6 = 1 \)[/tex]
- Hydrogen: [tex]\( 12 / 6 = 2 \)[/tex]
- Oxygen: [tex]\( 6 / 6 = 1 \)[/tex]
- Resulting formula: [tex]\( CH_2O \)[/tex]
- Conclusion: Yes, it matches [tex]\( CH_2O \)[/tex].
### Final List of Compounds Matching the Empirical Formula [tex]\( CH_2O \)[/tex]:
- [tex]\( C_2H_4O_2 \)[/tex]
- [tex]\( C_3H_6O_3 \)[/tex]
- [tex]\( C_5H_{10}O_5 \)[/tex]
- [tex]\( C_6H_{12}O_6 \)[/tex]
So, the correct answers are:
- [tex]\( C_2H_4O_2 \)[/tex]
- [tex]\( C_3H_6O_3 \)[/tex]
- [tex]\( C_5H_{10}O_5 \)[/tex]
- [tex]\( C_6H_{12}O_6 \)[/tex]
