Let the measure of [tex]$\overline{BCD} = a^{\circ}$[/tex]. Because [tex]$\overline{BCD}$[/tex] and [tex]$\overline{BAD}$[/tex] form a circle, and a circle measures [tex]$360^{\circ}$[/tex], the measure of [tex]$\overline{BAD}$[/tex] is [tex]$360 - a^{\circ}$[/tex]. Because of the Inscribed Angle theorem, [tex]$m \angle A = \frac{a}{2}$[/tex] degrees and [tex]$m \angle C = \frac{360 - a}{2}$[/tex] degrees. The sum of the measures of angles A and C is [tex]$\left(\frac{a}{2} + \frac{360 - a}{2}\right)$[/tex] degrees, which is equal to [tex]$\frac{360^{\circ}}{2}$[/tex], or [tex]$180^{\circ}$[/tex]. Therefore, angles A and C are supplementary because their measures add up to [tex]$180^{\circ}$[/tex].

Angles B and D are supplementary because the sum of the measures of the angles in a quadrilateral is [tex]$360^{\circ}$[/tex]. [tex]$m \angle A + m \angle C + m \angle B + m \angle D = 360^{\circ}$[/tex], and using substitution, [tex]$180^{\circ} + m \angle B + m \angle D = 360^{\circ}$[/tex], so [tex]$m \angle B + m \angle D = 180^{\circ}$[/tex].

What is the missing information in the paragraph proof?



Answer :

The missing information in the paragraph proof is the Inscribed Angle Theorem.

Let's break down the proof step by step:

1. Given Data:
- Let the measure of the arc [tex]\( \overline{BCD} = a^\circ \)[/tex].
- Since [tex]\( \overline{BCD} \)[/tex] and [tex]\( \overline{BAD} \)[/tex] form a complete circle, the measure of the arc [tex]\( \overline{BAD} \)[/tex] is [tex]\( 360^\circ - a^\circ \)[/tex].

2. Applying the Inscribed Angle Theorem:
- According to the Inscribed Angle Theorem, the measure of an inscribed angle is half of the measure of its intercepted arc.
- Therefore, the measure of angle [tex]\( \angle A \)[/tex] is [tex]\( \frac{a}{2} \)[/tex] degrees, since it intercepts the arc [tex]\( \overline{BCD} \)[/tex].
- Similarly, the measure of angle [tex]\( \angle C \)[/tex] is [tex]\( \frac{360 - a}{2} \)[/tex] degrees, since it intercepts the arc [tex]\( \overline{BAD} \)[/tex].

3. Summing Angles A and C:
- The sum of the measures of angles [tex]\( \angle A \)[/tex] and [tex]\( \angle C \)[/tex] is:
[tex]\[ m\angle A + m\angle C = \frac{a}{2} + \frac{360 - a}{2} \][/tex]
- Simplifying this, we have:
[tex]\[ \frac{a}{2} + \frac{360 - a}{2} = \frac{a + 360 - a}{2} = \frac{360}{2} = 180^\circ \][/tex]
- Therefore, angles [tex]\( \angle A \)[/tex] and [tex]\( \angle C \)[/tex] are supplementary because their measures add up to [tex]\( 180^\circ \)[/tex].

4. Angles in a Quadrilateral:
- The sum of the measures of all angles in a quadrilateral is [tex]\( 360^\circ \)[/tex].
[tex]\[ m\angle A + m\angle C + m\angle B + m\angle D = 360^\circ \][/tex]
- We know [tex]\( m\angle A + m\angle C = 180^\circ \)[/tex], so:
[tex]\[ 180^\circ + m\angle B + m\angle D = 360^\circ \][/tex]
- By subtracting 180° from both sides, we get:
[tex]\[ m\angle B + m\angle D = 180^\circ \][/tex]
- Therefore, angles [tex]\( \angle B \)[/tex] and [tex]\( \angle D \)[/tex] are also supplementary because their measures add up to [tex]\( 180^\circ \)[/tex].

To conclude, the missing information in the proof is the Inscribed Angle Theorem, which states that the measure of an inscribed angle is half the measure of its intercepted arc.