Let's solve each question one by one.
### 7. What is the quotient of -12 and -3?
To find the quotient of [tex]\(-12\)[/tex] and [tex]\(-3\)[/tex], we simply perform the division:
[tex]\[
\frac{-12}{-3} = 4.0
\][/tex]
So, the quotient is [tex]\(4.0\)[/tex].
### 8. Find [tex]\(6 \times (-6) \times 0 - (-8)\)[/tex]
First, we calculate the product of [tex]\(6\)[/tex], [tex]\(-6\)[/tex], and [tex]\(0\)[/tex]:
[tex]\[
6 \times (-6) \times 0 = 0
\][/tex]
Next, we subtract [tex]\(-8\)[/tex] from [tex]\(0\)[/tex], which is equivalent to adding [tex]\(8\)[/tex]:
[tex]\[
0 - (-8) = 0 + 8 = 8
\][/tex]
So, the value of the expression is [tex]\(8\)[/tex].
### 9. Find the median of the data: [tex]\(3, 4, 5, 6, 7, 3, 4\)[/tex]
To find the median, we first need to sort the data in ascending order:
Sorted data: [tex]\(3, 3, 4, 4, 5, 6, 7\)[/tex]
Since there are [tex]\(7\)[/tex] values, the median is the middle value, which is the 4th value in the sorted list:
[tex]\[
\text{Median} = 4
\][/tex]
So, the median of the data is [tex]\(4\)[/tex].
### 10. The mean of three numbers is 10. The mean of the other four numbers is 12. Find the mean of all seven numbers.
First, we determine the total sum of the first three numbers. Given that their mean is [tex]\(10\)[/tex]:
[tex]\[
\text{Sum of the first three numbers} = 10 \times 3 = 30
\][/tex]
Next, we determine the total sum of the other four numbers. Given that their mean is [tex]\(12\)[/tex]:
[tex]\[
\text{Sum of the next four numbers} = 12 \times 4 = 48
\][/tex]
Now, we find the total sum of all seven numbers:
[tex]\[
\text{Total sum of all numbers} = 30 + 48 = 78
\][/tex]
Finally, we calculate the mean of all seven numbers:
[tex]\[
\text{Mean of all seven numbers} = \frac{78}{7} \approx 11.14
\][/tex]
So, the mean of all seven numbers is approximately [tex]\(11.14\)[/tex].
