A newborn who weighs [tex]$2,500 \, g$[/tex] or less has a low birth weight. Use the information provided to find the z-score of a [tex]$2,500 \, g$[/tex] baby.

What is the z-score of a newborn who weighs [tex][tex]$4,000 \, g$[/tex][/tex]?

In the United States, birth weights of newborn babies are approximately normally distributed with a mean of [tex]\mu=3,500 \, g[/tex] and a standard deviation of [tex]\sigma=500 \, g[/tex].

[tex]
z = \frac{x - \mu}{\sigma}
[/tex]



Answer :

Let's find the [tex]\( z \)[/tex]-score for a newborn who weighs [tex]\( 4,000 \)[/tex] grams. We're given the mean ([tex]\(\mu\)[/tex]) and the standard deviation ([tex]\(\sigma\)[/tex]) of the birth weights. The mean weight of newborn babies is [tex]\(\mu = 3,500 \)[/tex] grams, and the standard deviation is [tex]\(\sigma = 500 \)[/tex] grams.

We use the formula for the [tex]\( z \)[/tex]-score:

[tex]\[ z = \frac{x - \mu}{\sigma} \][/tex]

where:
- [tex]\( x \)[/tex] is the observed value (the weight of the newborn in this case),
- [tex]\(\mu\)[/tex] is the mean,
- [tex]\(\sigma\)[/tex] is the standard deviation.

For a newborn weighing [tex]\( 4,000 \)[/tex] grams, we substitute the values into the formula:

[tex]\[ z = \frac{4,000 - 3,500}{500} \][/tex]

First, we calculate the difference between the weight of the newborn ([tex]\( x \)[/tex]) and the mean ([tex]\(\mu\)[/tex]):

[tex]\[ 4,000 - 3,500 = 500 \][/tex]

Next, we divide this difference by the standard deviation ([tex]\(\sigma\)[/tex]):

[tex]\[ z = \frac{500}{500} = 1.0 \][/tex]

Therefore, the [tex]\( z \)[/tex]-score of a newborn who weighs [tex]\( 4,000 \)[/tex] grams is [tex]\( 1.0 \)[/tex].